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Question

Let a matrix A = open square brackets table row 1 1 row 0 1 end table close square brackets & P =open square brackets table row cell fraction numerator square root of 3 over denominator 2 end fraction end cell cell fraction numerator 1 over denominator 2 end fraction end cell row cell negative fraction numerator 1 over denominator 2 end fraction end cell cell fraction numerator square root of 3 over denominator 2 end fraction end cell end table close square brackets Q = PAPT where PT is transpose of matrix P. Find PT Q2005 P is

  1. open square brackets table row 1 2005 row 0 1 end table close square brackets    
  2. fraction numerator 1 over denominator 4 end fraction open square brackets table row cell 1 plus 2005 square root of 3 end cell 6015 row 2005 cell 1 minus 2005 square root of 3 end cell end table close square brackets    
  3. fraction numerator 1 over denominator 4 end fraction open square brackets table row cell 1 plus 2005 square root of 3 end cell 2005 row 2005 cell 1 minus 2005 square root of 3 end cell end table close square brackets    
  4. open square brackets table row 2005 2005 row 0 1 end table close square brackets    

hintHint:

check whether inverse of P exists or not and then use the properties of invertible matrices while solving the expression.

The correct answer is: open square brackets table row 1 2005 row 0 1 end table close square brackets



    option A
    A2005  = [ 1 2005
    0     1]
    PTP = (1 0
    0           1)
    => PTP = I or PT = P-1
    Now, evaluating the required expression,
    PT Q 2005 P = PT   [(PAPT) (PAPT) (PAPT) (PAPT) (PAPT)….]P
    Since P is invertible, we can write
    (IA)(IA)(IA)….2005 times
    Or, I A2005 = A2005
    Now, calculating A2005 ,
    A = [1 1
    0 1]
    A2 = [1 2
    0 1]
    A3 = [1 3
    0 1]
    Similarly, A2005  = [ 1 2005
    0     1]

    an invertible matrix gives identity matrix as the product when multiplied with its inverse.

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    B) Reduces ammoniacal AgNO subscript 3 and gives yellow colour with NaOH plus straight I subscript 2
    C) does not reduce Tollens reagent but gives iodoform test
    D) n dehydration with conc. straight H subscript 2 SO subscript 4 gives a mixture of colourless gases

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