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Question

L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator 6 to the power of x minus 3 to the power of x minus 2 to the power of x plus 1 over denominator x squared end fraction

  1. log space 3 cross times log space 6
  2. log space 2 cross times log space 3
  3. log space 2 cross times log space 6
  4. log space 3 plus log space 2

hintHint:

We can apply L'Hopital's rule, also commonly spelled L'Hospital's rule, whenever direct substitution of a limit yields an indeterminate form. This means that the limit of a quotient of functions (i.e., an algebraic fraction) is equal to the limit of their derivatives.
In this question, we have to find value of L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator 6 to the power of x minus 3 to the power of x minus 2 to the power of x plus 1 over denominator x squared end fraction.

The correct answer is: log space 2 cross times log space 3


    L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator 6 to the power of x minus 3 to the power of x minus 2 to the power of x plus 1 over denominator x squared end fraction
    L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator 6 to the power of x minus 3 to the power of x minus 2 to the power of x plus 1 over denominator x squared end fraction space space left parenthesis 6 to the power of x space equals space 3 to the power of x cross times space 2 to the power of x right parenthesis
L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator left parenthesis 3 to the power of x minus 1 right parenthesis space cross times space left parenthesis 2 to the power of x minus 1 right parenthesis over denominator x squared end fraction
    We first try substitution :
    L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator left parenthesis 3 to the power of x minus 1 right parenthesis space cross times space left parenthesis 2 to the power of x minus 1 right parenthesis over denominator x squared end fraction =L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator left parenthesis 3 to the power of 0 minus 1 right parenthesis space cross times space left parenthesis 2 to the power of 0 minus 1 right parenthesis over denominator 0 end fraction space equals space 0 over 0
    Since the limit is in the form 0 over 0, it is indeterminate—we don’t yet know what is it. We need to do some work to put it in a form where we can determine the limit.
    L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator left parenthesis 3 to the power of x minus 1 right parenthesis space cross times space left parenthesis 2 to the power of x minus 1 right parenthesis over denominator x squared end fraction         (  L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator left parenthesis a to the power of x minus 1 right parenthesis space over denominator x end fraction =log subscript e a  )
    L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator left parenthesis 3 to the power of x minus 1 right parenthesis over denominator x end fraction space cross times space L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator left parenthesis 2 to the power of x minus 1 right parenthesis over denominator x end fraction
    so Now,
    log subscript e 3 cross times log subscript e 2

    We can only apply the L’Hospital’s rule if the direct substitution returns an indeterminate form, that means 0 over 0 space o r space fraction numerator plus-or-minus infinity over denominator plus-or-minus infinity end fraction.

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