Maths-
General
Easy

Question

stack L t with x not stretchy rightwards arrow negative 1.5 below cos to the power of negative 1 end exponent space open parentheses fraction numerator x plus 3 over denominator 3 end fraction close parentheses

  1. straight pi over 2
  2. straight pi over 6
  3. straight pi over 3
  4. straight pi over 4

hintHint:

Finding limits for the vast majority of points for a given function is as simple as substituting the number that x approaches into the function. In this question, we have to find value of stack L t with x not stretchy rightwards arrow negative 1.5 below cos to the power of negative 1 end exponent space open parentheses fraction numerator x plus 3 over denominator 3 end fraction close parentheses.

The correct answer is: straight pi over 3


    stack L t with x not stretchy rightwards arrow negative 1.5 below cos to the power of negative 1 end exponent space open parentheses fraction numerator x plus 3 over denominator 3 end fraction close parentheses
    On substituting, We get
    stack L t with x not stretchy rightwards arrow negative 1.5 below cos to the power of negative 1 end exponent space open parentheses fraction numerator x plus 3 over denominator 3 end fraction close parentheses      (  Value of cos to the power of negative 1 end exponent left parenthesis fraction numerator negative 1.5 space plus 3 over denominator 3 end fraction right parenthesis space equals space cos to the power of negative 1 end exponent left parenthesis 1 half right parenthesisπ/6  )
    stack L t with x not stretchy rightwards arrow negative 1.5 below straight pi over 6 space space T h e r e f o r e comma space fraction numerator straight pi over denominator 6 space end fraction space i s space t h e space f i n a l space a n s w e r.

    A limit is the value that the output of a function approaches as the input of the function approaches a given value.

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