Number of positive integers that are divisiors of atleast one of the numbers is

The correct answer is: 435

Number of divisors of 1010 = 210 510 11 11 = 121 ....(1)
ly Number of divisors of 157 = 37 57 8 8 = 64 ....(2)
and Number of divisors of 811 = 211 322 12 23 = 276 ....(3)
common in (1) and (2) = 8 (because of the presence of 57 in both)
common in (2) and (3) = 8 (because of the presence of in both)
common in (3) and (1) = 11 (because of the presence of 2in both)
However we have not counted the factor which divide all the three number i.e. 1
hence final answer = 121 + 64 + 276 - (8 + 8 + 11) + 1 = 435