Maths-
General
Easy

Question

Ray OQ bisects ∠𝑃𝑂𝑅. Find 𝑚∠𝑃𝑂𝑅 if 𝑚∠𝑃𝑂𝑄 = 24°.

The correct answer is: 48 digres


    • Hint:
      • Angle bisector bisects the angle in two equal parts.
      • If the measure of angle is 2xo then the angle bisector will bisect it in two parts measuring xo each.
    • Step by step explanation: 
      • Given: 
    Ray OQ bisects ∠𝑃𝑂𝑅
    𝑚∠POQ = 24°
    • Step 1:
    • Let 𝑚∠POQ = xo
    • As we know angle bisectors bisects the angle in two equal parts.
    Hence,
    𝑚∠POQ = 𝑚∠QOR = xo
    • Step 2:
    From figure it is clear that:
    ∠POQ + ∠QOR = ∠POR
    x + x = ∠POR
    2x = ∠POR
    We know that x = 24o
    ∴ ∠POR = 2x = 2(24)
    ∠POR = 48o.
    • Final Answer: 
    Hence, 𝑚∠𝑃𝑂𝑅 is 48o.

    Related Questions to study

    General
    Maths-

    Find: a) QR
    b) 𝑚∠𝑃𝑄𝑇

    Find: a) QR
    b) 𝑚∠𝑃𝑄𝑇

    Maths-General
    General
    Maths-

    A sports store sells a total of 70- Soccer balls in one month and collects a total of $2,400. Write and Solve a System of equations to determine how many of each type of soccer ball were sold.

    A sports store sells a total of 70- Soccer balls in one month and collects a total of $2,400. Write and Solve a System of equations to determine how many of each type of soccer ball were sold.

    Maths-General
    General
    Maths-

    Ray OQ bisects ∠𝑃𝑂𝑅. Find the value of x.

    Ray OQ bisects ∠𝑃𝑂𝑅. Find the value of x.

    Maths-General
    parallel
    General
    Maths-

    Identify all pairs of congruent angles and congruent segments.

    Identify all pairs of congruent angles and congruent segments.

    Maths-General
    General
    Maths-

    ∠𝐴 & ∠𝐵 are complementary.  ∠𝐵 & ∠𝐶 are complementary. Prove: ∠𝐴 ≅  ∠𝐶

    ∠𝐴 & ∠𝐵 are complementary.  ∠𝐵 & ∠𝐶 are complementary. Prove: ∠𝐴 ≅  ∠𝐶

    Maths-General
    General
    Maths-

    Given: Ray OR bisects ∠𝑃𝑂𝑆.
    Prove: 𝑚∠1 = 𝑚∠2

    Given: Ray OR bisects ∠𝑃𝑂𝑆.
    Prove: 𝑚∠1 = 𝑚∠2

    Maths-General
    parallel
    General
    Maths-

    Solve the following by using the method of substitution
    Y = - 2X-3
    Y = - X-4

    Solve the following by using the method of substitution
    Y = - 2X-3
    Y = - X-4

    Maths-General
    General
    Maths-

    Solve the system of equations by elimination :
    X - 2Y = 1
    2X + 3Y= - 12

    Solve the system of equations by elimination :
    X - 2Y = 1
    2X + 3Y= - 12

    Maths-General
    General
    Maths-

    Solve the equation. Write a reason for each step.
    𝑥 − 2 + 3(𝑥 + 2) = 3𝑥 + 10

    Solve the equation. Write a reason for each step.
    𝑥 − 2 + 3(𝑥 + 2) = 3𝑥 + 10

    Maths-General
    parallel
    General
    Maths-

    Use Substitution to solve each system of equations :
    6X - 3Y = -6
    Y = 2X + 2

    Use Substitution to solve each system of equations :
    6X - 3Y = -6
    Y = 2X + 2

    Maths-General
    General
    Maths-

    Given: 𝑚∠𝑃 = 30°, 𝑚∠𝑄 = 30° , 𝑚∠𝑄 = 𝑚∠𝑅
    Prove: 𝑚∠𝑃 ≅ 𝑚∠𝑅 = 30°

    Given: 𝑚∠𝑃 = 30°, 𝑚∠𝑄 = 30° , 𝑚∠𝑄 = 𝑚∠𝑅
    Prove: 𝑚∠𝑃 ≅ 𝑚∠𝑅 = 30°

    Maths-General
    General
    Maths-

    Use the given information and the diagram to prove the statement.
    Given: 𝑚∠𝑃𝑀𝐶 + 𝑚∠𝑃𝑀𝐷 = 180° and 𝑚∠𝑃𝑀𝐶 = 150°
    Prove: 𝑚∠𝑃𝑀𝐷 = 30°

    Use the given information and the diagram to prove the statement.
    Given: 𝑚∠𝑃𝑀𝐶 + 𝑚∠𝑃𝑀𝐷 = 180° and 𝑚∠𝑃𝑀𝐶 = 150°
    Prove: 𝑚∠𝑃𝑀𝐷 = 30°

    Maths-General
    parallel
    General
    Maths-

    Solve the system of equations by elimination :
    3X + 2Y = 8
    X + 4Y = - 4

    Solve the system of equations by elimination :
    3X + 2Y = 8
    X + 4Y = - 4

    Maths-General
    General
    Maths-

    Give a two-column proof.
    Given:

    Prove: PR = 25 in

    Give a two-column proof.
    Given:

    Prove: PR = 25 in

    Maths-General
    General
    Maths-

    Use Substitution to solve each system of equations :
    - 3X - Y = 7
    X + 2Y = 6

    Use Substitution to solve each system of equations :
    - 3X - Y = 7
    X + 2Y = 6

    Maths-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.