Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

$open parentheses sin to the power of 8 space 75 to the power of ring operator minus cos to the power of 8 space 75 to the power of ring operator close parentheses$ =

$\frac{7 \sqrt{3}}{8}$
$\frac{3 \sqrt{3}}{8}$
$\frac{3 \sqrt{3}}{16}$
$\frac{7 \sqrt{3}}{16}$

Hint:

In this question, we have to find the value of the given equation. For that we will simplify the equation using some trigonometric identities and later substitute the value to get the required value.

The correct answer is: $fraction numerator 7 square root of 3 over denominator 16 end fraction$

$space space space open parentheses sin to the power of 8 space 75 to the power of ring operator minus cos to the power of 8 space 75 to the power of ring operator close parentheses equals sin to the power of 8 open parentheses 90 minus 15 close parentheses degree minus cos to the power of 8 left parenthesis 90 minus 15 right parenthesis degree equals cos to the power of 8 15 degree minus sin to the power of 8 15 degree equals open parentheses cos to the power of 4 15 degree plus sin to the power of 4 15 degree close parentheses open parentheses cos to the power of 4 15 degree minus sin to the power of 4 15 degree close parentheses equals open parentheses open parentheses cos squared 15 degree plus sin squared 15 degree close parentheses squared minus 2 sin squared 15 degree. cos squared space 15 degree close parentheses open parentheses cos squared 15 degree plus sin squared 15 degree close parentheses open parentheses cos squared 15 degree minus sin squared 15 degree close parentheses equals open parentheses 1 minus open parentheses 2 sin space 15 degree. cos 15 degree close parentheses squared over 2 close parentheses 1 cross times cos open parentheses 2 cross times 15 close parentheses degree equals open parentheses 1 minus fraction numerator s i n squared 30 degree over denominator 2 end fraction close parentheses cos space 30 degree equals open parentheses 1 minus 1 over 8 close parentheses fraction numerator square root of 3 over denominator 2 end fraction equals 7 over 8. fraction numerator square root of 3 over denominator 2 end fraction equals fraction numerator 7 square root of 3 over denominator 16 end fraction$

Related Questions to study

If $tan space alpha equals fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction comma tan space beta equals fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction$ and $tan space gamma equals square root of x to the power of negative 3 end exponent plus x to the power of negative 2 end exponent plus x to the power of negative 1 end exponent end root$ then $alpha plus beta$ =

If $tan space alpha equals fraction numerator 1 over denominator square root of x open parentheses x squared plus x plus 1 close parentheses end root end fraction comma tan space beta equals fraction numerator square root of x over denominator square root of x squared plus x plus 1 end root end fraction$ and $tan space gamma equals square root of x to the power of negative 3 end exponent plus x to the power of negative 2 end exponent plus x to the power of negative 1 end exponent end root$ then $alpha plus beta$ =

If $tan space left parenthesis pi cos space theta right parenthesis equals cot space left parenthesis pi sin space theta right parenthesis comma 0 less than theta less than fraction numerator 3 pi over denominator 4 end fraction$ then $sin space open parentheses theta plus pi over 4 close parentheses equals$

If $tan space left parenthesis pi cos space theta right parenthesis equals cot space left parenthesis pi sin space theta right parenthesis comma 0 less than theta less than fraction numerator 3 pi over denominator 4 end fraction$ then $sin space open parentheses theta plus pi over 4 close parentheses equals$

The minimum value $m space equals bold space 2 cos space theta plus fraction numerator 1 over denominator sin invisible function application theta end fraction plus square root of 2 tan space theta space text in end text open parentheses 0 comma pi over 2 close parentheses$ is

The minimum value $m space equals bold space 2 cos space theta plus fraction numerator 1 over denominator sin invisible function application theta end fraction plus square root of 2 tan space theta space text in end text open parentheses 0 comma pi over 2 close parentheses$ is

parallel

In the adjoining figure, $stack left floor a with _ below equals left floor b$ and $left floor c equals left floor d comma$ then $left floor b plus left floor c equals$

In the adjoining figure, $stack left floor a with _ below equals left floor b$ and $left floor c equals left floor d comma$ then $left floor b plus left floor c equals$

In the figure, $a equals 4 x to the power of ring operator end exponent$ and $b equals left parenthesis 2.5 x plus 24 right parenthesis to the power of ring operator end exponent comma$ then the value of x =

In the figure, $a equals 4 x to the power of ring operator end exponent$ and $b equals left parenthesis 2.5 x plus 24 right parenthesis to the power of ring operator end exponent comma$ then the value of x =

In the following figure, the value of x =

In the following figure, the value of x =

parallel

Using information given in the following figure, the value of x and y is

Using information given in the following figure, the value of x and y is

In figure, the sides QP and RQ of $triangle P Q R$ are produced to points S and T respectively. If $stack S P R with _ below equals 135 to the power of ring operator end exponent$ and $open floor P Q T equals 110 to the power of ring operator end exponent close$ then $stack P R Q with _ below equals$

In figure, the sides QP and RQ of $triangle P Q R$ are produced to points S and T respectively. If $stack S P R with _ below equals 135 to the power of ring operator end exponent$ and $open floor P Q T equals 110 to the power of ring operator end exponent close$ then $stack P R Q with _ below equals$

In the given figure, if $P Q R equals 70 to the power of ring operator end exponent$ then $∣ A B C equals$

In the given figure, if $P Q R equals 70 to the power of ring operator end exponent$ then $∣ A B C equals$

parallel

From the given figure, the value of ‘a’ is

From the given figure, the value of ‘a’ is

In the following figure, AB is parallel to CD , then the value of x in degrees is

In the following figure, AB is parallel to CD , then the value of x in degrees is

In the given figure, $l parallel to m$ then the value of x =

In the given figure, $l parallel to m$ then the value of x =

parallel

In the given figure, $stack A B with bar on top$ is parallel to CD, then x =

In the given figure, $stack A B with bar on top$ is parallel to CD, then x =

In the figure, AB is parallel to CD , then x =

In the figure, AB is parallel to CD , then x =

In the adjoining figure, two straight lines PQ and RS intersect each other at O. If then the values of a,b and c are .........., .......... and ..............

In the adjoining figure, two straight lines PQ and RS intersect each other at O. If then the values of a,b and c are .........., .......... and ..............

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.