Maths-

General

Easy

Question

Solve the equation $square root of 2 x minus 5 end root minus square root of x minus 3 end root equals 1$

hint Hint:

Rearrange the equation and then solve for x.

The correct answer is: ⇒ x = 7

Complete step by step solution:
Here we have the equation $square root of 2 x minus 5 end root minus square root of x minus 3 end root equals 1$
$not stretchy rightwards double arrow square root of 2 x minus 5 end root equals 1 plus square root of x minus 3 end root$
On squaring both the sides, we have $2 x minus 5 equals left parenthesis 1 plus square root of x minus 3 end root right parenthesis left parenthesis 1 plus square root of x minus 3 end root right parenthesis$
$not stretchy rightwards double arrow 2 x minus 5 equals 1 plus 2 square root of x minus 3 end root plus x minus 3$
On subtracting, x and -2 from both the sides, we get
$not stretchy rightwards double arrow x minus 3 equals 2 square root of x minus 3 end root$
On squaring both the sides, we get
$table attributes columnspacing 1em end attributes row cell left parenthesis x minus 3 right parenthesis squared equals 4 left parenthesis x minus 3 right parenthesis end cell row cell not stretchy rightwards double arrow x minus 3 equals 4 end cell row cell not stretchy rightwards double arrow x equals 7 end cell end table$

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Solve the equation

Rearrange the equation and then solve for x.

The correct answer is: ⇒ x = 7

Complete step by step solution:Here we have the equation On squaring both the sides, we have On subtracting, x and -2 from both the sides, we getOn squaring both the sides, we get

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