Maths-
General
Easy

Question

Solve the equation square root of x plus 2 end root plus square root of 3 x plus 4 end root equals 2

hintHint:

Rearrange the equation and then solve for x.

The correct answer is: x = 7 or -1


    Complete step by step solution:
    Here we have the equation square root of x plus 2 end root plus square root of 3 x plus 4 end root equals 2

    not stretchy rightwards double arrow square root of x plus 2 end root equals 2 minus square root of 3 x plus 4 end root
    On squaring both the sides, we have x plus 2 equals left parenthesis 2 minus square root of 3 x plus 4 end root right parenthesis left parenthesis 2 minus square root of 3 x plus 4 end root right parenthesis

    not stretchy rightwards double arrow x plus 2 equals 4 minus 4 square root of 3 x plus 4 end root plus 3 x plus 4
    On subtracting, 3x and 8 from both the sides, we get

    not stretchy rightwards double arrow negative 2 x minus 6 equals negative 4 square root of 3 x plus 4 end root
    On squaring both the sides, we get

     table attributes columnspacing 1em end attributes row cell left parenthesis negative 2 x minus 6 right parenthesis squared equals 16 left parenthesis 3 x plus 4 right parenthesis end cell row cell not stretchy rightwards double arrow 4 x squared plus 24 x plus 36 equals 48 x plus 64 end cell row cell not stretchy rightwards double arrow 4 x squared minus 24 x minus 28 equals 0 end cell end table
    Now, this is a quadratic equation with a = 4, b = -24, c = -28
    Roots can be found with, x equals fraction numerator negative b plus-or-minus square root of b squared minus 4 a c end root over denominator 2 a end fraction
    x equals fraction numerator 24 plus-or-minus square root of 576 minus 4 cross times 1 cross times negative 28 end root over denominator 2 cross times 4 end fraction
    On solving, we get x = 7 or -1

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