Maths-
General
Easy

Question

Stanley bought five packs of Yu-Gi-Oh cards, $7 worth of bubble gum, and then eight more packs of Yu-Gi-Oh cards. Simon bought four packs of Yu-Gi-Oh cards, $10 worth of Cheetos, $12 worth of Mt. Dew, and then six more packs of Yu-Gi-Oh cards. If they paid the same amount, how much was each pack of Yu-Gi-Oh cards?

Hint:

  • Hint:
○ Form the equation according to given information.
○ Take variable value as alphabet and solve equation to get the value of variable.

The correct answer is: $5.


    • Step by step explanation:
    ○ Given:
    rightwards double arrowStanley buys 13 pack of Yu-Gi-Oh cards + $7 bubble gum
    rightwards double arrowSimon buys 10 pack of Yu-Gi-Oh cards + $10 cheetos + $12 Mt.dew
    ○    Step 1:
    ○    Let price of 1 pack of Yu-Gi-Oh cards be x.
    First consider case of Stanley
    Total money spent = 13x + 7
    Now consider case of Simon:
    Total money spent = 10x + 10 + 12
    ○ Step 2:
    ○ Equate money spent by both.

    rightwards double arrow(13x + 7 ) = (10x + 10 + 12 )

    rightwards double arrow(13x + 7 ) = (10x + 22 )

    rightwards double arrow13x - 10x = 22 - 7

    rightwards double arrow3x = 15

    rightwards double arrowx = 15 over 3

    rightwards double arrowx = 5

    • Final Answer:
    Hence, the price of 1 pack is $5.

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