Question
The eccentricity of the hyperbola with asymptotes 3x + 4y = 2 and 4x – 3y = 2 is
 3
 2

 4
Hint:
The eccentricity of a hyperbola is always greater than 1. i.e. e > 1. The eccentricity of a hyperbola can be taken as the ratio of the distance of the point on the hyperbole, from the focus, and its distance from the directrix.
Eccentricity = Distance from Focus/Distance from Directrix
The correct answer is:
We have been given two asymptotes i.e. 3x + 4y = 2 and 4x – 3y = 2
First find out their slopes
From above we can see that m1 and m2 are negative inverse of each other that means both are perpendicular to each other.
It is a rectangular hyperbola and it has fixed eccentricity.
Thus eccentricity =
Related Questions to study
The number of ways that '6' rings can be worn on the 4  fingers of one hand is
It is important to note that we have used a basic fundamental principle of counting to find the total ways. Also, it is important to notice that each ring has 4 ways as it has not been given that each finger must have at least one ring. So, there can be 6 rings in a finger alone and remaining all the fingers empty.
The number of ways that '6' rings can be worn on the 4  fingers of one hand is
It is important to note that we have used a basic fundamental principle of counting to find the total ways. Also, it is important to notice that each ring has 4 ways as it has not been given that each finger must have at least one ring. So, there can be 6 rings in a finger alone and remaining all the fingers empty.