The function f is defined by f(r) = (r - 4) (r + 1)². If f (h - 3) = 0, what is one possible value of h ?

The correct answer is: 7

HINT: Substitute (h - 3) in places of r in the given function and then proceed.
Complete step by step solution:
Given function is f(r) = (r - 4) (r + 1)²
On substituting (h-3) in places of r in the given function,
we get, f(h - 3) = (h - 3 - 4) (h - 3 + 1)²
I. e, 0 = (h - 7) (h - 2)²
Then h can take the values 7 or 2.
So one possible value of h is 7.