Maths-
General
Easy

Question

The function f open parentheses x close parentheses equals open vertical bar 2 s g n blank 2 x close vertical bar plus 2 has

  1. Jump discontinuity    
  2. Removal discontinuity    
  3. Infinite discontinuity    
  4. No discontinuity at x equals 0    

The correct answer is: Removal discontinuity


    stack Lt with x rightwards arrow 0 below invisible function application fraction numerator 1 minus c o s open parentheses 1 minus c o s x close parentheses over denominator x to the power of 4 end exponent end fraction

    Related Questions to study

    General
    Chemistry-

    In the, following compounds, the order of basicity is :
    I)
    II)
    III)
    IV)

    In the, following compounds, the order of basicity is :
    I)
    II)
    III)
    IV)

    Chemistry-General
    General
    Chemistry-

    Arrange the following carbocations in decreasing order of stability:
    I) C H subscript 3 end subscript C H subscript 2 end subscript stack C H subscript 2 end subscript with plus on top
    II)
    III) C H subscript 3 end subscript minus stack C with plus on top H minus C H subscript 3 end subscript
    IV) 

    Arrange the following carbocations in decreasing order of stability:
    I) C H subscript 3 end subscript C H subscript 2 end subscript stack C H subscript 2 end subscript with plus on top
    II)
    III) C H subscript 3 end subscript minus stack C with plus on top H minus C H subscript 3 end subscript
    IV) 

    Chemistry-General
    General
    Maths-

    If f open parentheses x plus y close parentheses equals f open parentheses x close parentheses f open parentheses y close parentheses and f open parentheses x close parentheses equals 1 plus g open parentheses x close parentheses h open parentheses x close parentheses where stack Lt with x rightwards arrow 0 below invisible function application g open parentheses x close parentheses equals 0 comma stack Lt with x rightwards arrow 0 below invisible function application h open parentheses x close parentheses exists, then f open parentheses x close parentheses is continuous on

    If f open parentheses x plus y close parentheses equals f open parentheses x close parentheses f open parentheses y close parentheses and f open parentheses x close parentheses equals 1 plus g open parentheses x close parentheses h open parentheses x close parentheses where stack Lt with x rightwards arrow 0 below invisible function application g open parentheses x close parentheses equals 0 comma stack Lt with x rightwards arrow 0 below invisible function application h open parentheses x close parentheses exists, then f open parentheses x close parentheses is continuous on

    Maths-General
    parallel
    General
    Maths-

    The value of f (0) so that the function f open parentheses x close parentheses equals fraction numerator l o g open parentheses 1 plus fraction numerator x over denominator a end fraction close parentheses minus l o g open parentheses 1 minus fraction numerator x over denominator b end fraction close parentheses over denominator x end fraction open parentheses x not equal to 0 close parentheses blankis continuous at x equals 0 blank is

    For such questions, we should know formula for different limits.

    The value of f (0) so that the function f open parentheses x close parentheses equals fraction numerator l o g open parentheses 1 plus fraction numerator x over denominator a end fraction close parentheses minus l o g open parentheses 1 minus fraction numerator x over denominator b end fraction close parentheses over denominator x end fraction open parentheses x not equal to 0 close parentheses blankis continuous at x equals 0 blank is

    Maths-General

    For such questions, we should know formula for different limits.

    General
    Physics-

    Light of two different frequencies whose photons have energies 1 e V and 2.5 e V respectively, successively illuminates a metal of work function 0.5 e V. The ratio of maximum kinetic energy of the emitted electron will be

    Light of two different frequencies whose photons have energies 1 e V and 2.5 e V respectively, successively illuminates a metal of work function 0.5 e V. The ratio of maximum kinetic energy of the emitted electron will be

    Physics-General
    General
    Physics-

    4 eV is the energy of the incident photon and the work function in 2 e V. What is the stopping potential

    4 eV is the energy of the incident photon and the work function in 2 e V. What is the stopping potential

    Physics-General
    parallel
    General
    Physics-

    The work functions for sodium and copper are 2 e V and 4 e V. Which of them is suitable for a photocell with 4000 text Å end text light

    The work functions for sodium and copper are 2 e V and 4 e V. Which of them is suitable for a photocell with 4000 text Å end text light

    Physics-General
    General
    Physics-

    When yellow light is incident on a surface, no electrons are emitted while green light can emit. If red light is incident on the surface, then

    When yellow light is incident on a surface, no electrons are emitted while green light can emit. If red light is incident on the surface, then

    Physics-General
    General
    Physics-

    As the intensity of incident light increases

    As the intensity of incident light increases

    Physics-General
    parallel
    General
    Physics-

    The work function of a photoelectric material is 3.3 eV. The threshold frequency will be equal to

    The work function of a photoelectric material is 3.3 eV. The threshold frequency will be equal to

    Physics-General
    General
    Physics-

    When light falls on a metal surface, the maximum kinetic energy of the emitted photo-electrons depends upon

    When light falls on a metal surface, the maximum kinetic energy of the emitted photo-electrons depends upon

    Physics-General
    General
    Maths-

    f(x)=open curly brackets table row cell fraction numerator e to the power of a x end exponent minus e to the power of x end exponent minus x over denominator x to the power of 2 end exponent end fraction blank comma end cell cell x not equal to 0 end cell row cell fraction numerator 3 over denominator 2 end fraction blank comma end cell cell x equals 0 end cell end table close , the value of ‘a’ so that f is continuous function is

    f(x)=open curly brackets table row cell fraction numerator e to the power of a x end exponent minus e to the power of x end exponent minus x over denominator x to the power of 2 end exponent end fraction blank comma end cell cell x not equal to 0 end cell row cell fraction numerator 3 over denominator 2 end fraction blank comma end cell cell x equals 0 end cell end table close , the value of ‘a’ so that f is continuous function is

    Maths-General
    parallel
    General
    Physics-

    The energy of a photon of light with wavelength 5000 text Å end text is approximately 2.5 eV. This way the energy of an X-ray photon with wavelength 1text  Å  end textwould be

    The energy of a photon of light with wavelength 5000 text Å end text is approximately 2.5 eV. This way the energy of an X-ray photon with wavelength 1text  Å  end textwould be

    Physics-General
    General
    Physics-

    The energy of a photon of wavelength lambda is given by

    The energy of a photon of wavelength lambda is given by

    Physics-General
    General
    Physics-

    The de-Broglie wavelength of a neutron at 27°C is lambda. What will be its wavelength at 927°C

    The de-Broglie wavelength of a neutron at 27°C is lambda. What will be its wavelength at 927°C

    Physics-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.