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# The locus of P such that PA^{2} + PB^{2} = 10 where A = (2, 0) and B = (4, 0) is

- x
^{2} + y^{2} + 6x + 5 = 0
- x
^{2} – y^{2} – 6x + 5 = 0
- x
^{2} + y^{2} – 6x +5 = 0
- None

^{2}+ y^{2}+ 6x + 5 = 0^{2}– y^{2}– 6x + 5 = 0^{2}+ y^{2}– 6x +5 = 0Hint:

### In this question, we have to find the locus of P such that where A = (2, 0) and B = (4, 0). A locus is a set of points, in geometry, which satisfies a given condition or situation for a shape or a figure. For we will substitute the value of A and B in the given equation and simplify it to get the required equation.

## The correct answer is: x^{2} + y^{2} – 6x +5 = 0

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