Maths-
General
Easy

Question

The measure of an interior angle of a regular polygon is given as 108 degrees. Find the number of sides in the polygon:

  1. 6
  2. 5
  3. 7
  4. 8

The correct answer is: 5


    Sum of the measure of an interior angle= (n-2)180

    We have given the measure of an interior angle of a regular polygon is 108. If we multiply n with measure of an interior angle we would get sum of an interior angles of polygon.

    108n= 180*(n-2)

    108n= 180n-360

    180n-108n=360

    72n=360

    n= 360/72=5.

    Related Questions to study

    General
    Maths-

    Find the sum of the measures of the interior angles of convex polygon: Decagon

    Find the sum of the measures of the interior angles of convex polygon: Decagon

    Maths-General
    General
    Maths-

    Find the sum of the measures of the interior angles of convex polygon: Heptagon

    Find the sum of the measures of the interior angles of convex polygon: Heptagon

    Maths-General
    General
    Maths-

    Find the sum of the measures of the interior angles of convex polygon: Nonagon

    Find the sum of the measures of the interior angles of convex polygon: Nonagon

    Maths-General
    parallel
    General
    Maths-

    Divide the fractions. 4/5 divided by 6

    Divide the fractions. 4/5 divided by 6

    Maths-General
    General
    Maths-

    Convert 3/2 into percentage.

    Convert 3/2 into percentage.

    Maths-General
    General
    Maths-

    Convert 3/8 into percentage.

    Convert 3/8 into percentage.

    Maths-General
    parallel
    General
    Maths-

    Convert mixed fraction into improper fraction. 3 1/8

    Convert mixed fraction into improper fraction. 3 1/8

    Maths-General
    General
    Chemistry-

    In octahedral complexes the filling of t subscript 2 g end subscript orbitals decreases the energy of a complex, that is makes it more stable by negative 0.4 capital delta subscript 0 end subscript per electron. Filling the e subscript g end subscript orbitals increases the energy by plus 0.6 capital delta subscript 0 end subscript per electron. The total crystal field stabilization energy is given by
    C F S E invisible function application left parenthesis octahedral right parenthesis equals negative 0.4 capital delta subscript 0 end subscript open parentheses t subscript 2 g end subscript close parentheses plus 0.6 capital delta subscript 0 end subscript open parentheses e subscript g end subscript close parentheses

    The CFSE increases the thermodynamic stability of the complexes i.e it affects the actual lattice energy over the theoretically calculated energy that does not take CFSE it into account. In studying tetrahedral complexes a regular tetrahedron is related to a cube. One atom is at the centre and four of eight corners are occupied by the ligands. The directions of x comma y comma z point to the centres of the faces of the cube . The directions of the approach of the ligands does not coincide exactly with the atomic orbitals.
    In these complexes the e subscript g end subscript orbitals are more stable compared to the t subscript 2 g end subscript orbitals.
    Considering M n to the power of 2 plus end exponent if the measured lattice energy is XkJ/mol and the calculated lattice energy is YkJ/mol then their relation between X and Y in a strong and a weak ligand field respectively is

    In octahedral complexes the filling of t subscript 2 g end subscript orbitals decreases the energy of a complex, that is makes it more stable by negative 0.4 capital delta subscript 0 end subscript per electron. Filling the e subscript g end subscript orbitals increases the energy by plus 0.6 capital delta subscript 0 end subscript per electron. The total crystal field stabilization energy is given by
    C F S E invisible function application left parenthesis octahedral right parenthesis equals negative 0.4 capital delta subscript 0 end subscript open parentheses t subscript 2 g end subscript close parentheses plus 0.6 capital delta subscript 0 end subscript open parentheses e subscript g end subscript close parentheses

    The CFSE increases the thermodynamic stability of the complexes i.e it affects the actual lattice energy over the theoretically calculated energy that does not take CFSE it into account. In studying tetrahedral complexes a regular tetrahedron is related to a cube. One atom is at the centre and four of eight corners are occupied by the ligands. The directions of x comma y comma z point to the centres of the faces of the cube . The directions of the approach of the ligands does not coincide exactly with the atomic orbitals.
    In these complexes the e subscript g end subscript orbitals are more stable compared to the t subscript 2 g end subscript orbitals.
    Considering M n to the power of 2 plus end exponent if the measured lattice energy is XkJ/mol and the calculated lattice energy is YkJ/mol then their relation between X and Y in a strong and a weak ligand field respectively is

    Chemistry-General
    General
    Chemistry-

    In octahedral complexes the filling of t subscript 2 g end subscript orbitals decreases the energy of a complex, that is makes it more stable by negative 0.4 capital delta subscript 0 end subscript per electron. Filling the e subscript g end subscript orbitals increases the energy by plus 0.6 capital delta subscript 0 end subscript per electron. The total crystal field stabilization energy is given by
    C F S E invisible function application left parenthesis octahedral right parenthesis equals negative 0.4 capital delta subscript 0 end subscript open parentheses t subscript 2 g end subscript close parentheses plus 0.6 capital delta subscript 0 end subscript open parentheses e subscript g end subscript close parentheses

    The CFSE increases the thermodynamic stability of the complexes i.e it affects the actual lattice energy over the theoretically calculated energy that does not take CFSE it into account. In studying tetrahedral complexes a regular tetrahedron is related to a cube. One atom is at the centre and four of eight corners are occupied by the ligands. The directions of x comma y comma z point to the centres of the faces of the cube . The directions of the approach of the ligands does not coincide exactly with the atomic orbitals.
    In these complexes the e subscript g end subscript orbitals are more stable compared to the t subscript 2 g end subscript orbitals.
    During the formation of a tetrahedral complex the angle between the eg orbital and the central metal is X to the power of ring operator end exponent and that of t subscript 2 g end subscript orbital and the central metal is Y to the power of ring operator end exponent then X to the power of 0 end exponent minus Y to the power of ring operator end exponent is.

    In octahedral complexes the filling of t subscript 2 g end subscript orbitals decreases the energy of a complex, that is makes it more stable by negative 0.4 capital delta subscript 0 end subscript per electron. Filling the e subscript g end subscript orbitals increases the energy by plus 0.6 capital delta subscript 0 end subscript per electron. The total crystal field stabilization energy is given by
    C F S E invisible function application left parenthesis octahedral right parenthesis equals negative 0.4 capital delta subscript 0 end subscript open parentheses t subscript 2 g end subscript close parentheses plus 0.6 capital delta subscript 0 end subscript open parentheses e subscript g end subscript close parentheses

    The CFSE increases the thermodynamic stability of the complexes i.e it affects the actual lattice energy over the theoretically calculated energy that does not take CFSE it into account. In studying tetrahedral complexes a regular tetrahedron is related to a cube. One atom is at the centre and four of eight corners are occupied by the ligands. The directions of x comma y comma z point to the centres of the faces of the cube . The directions of the approach of the ligands does not coincide exactly with the atomic orbitals.
    In these complexes the e subscript g end subscript orbitals are more stable compared to the t subscript 2 g end subscript orbitals.
    During the formation of a tetrahedral complex the angle between the eg orbital and the central metal is X to the power of ring operator end exponent and that of t subscript 2 g end subscript orbital and the central metal is Y to the power of ring operator end exponent then X to the power of 0 end exponent minus Y to the power of ring operator end exponent is.

    Chemistry-General
    parallel
    General
    Chemistry-

    In octahedral complexes the filling of t subscript 2 g end subscript orbitals decreases the energy of a complex, that is makes it more stable by negative 0.4 capital delta subscript 0 end subscript per electron. Filling the e subscript g end subscript orbitals increases the energy by plus 0.6 capital delta subscript 0 end subscript per electron. The total crystal field stabilization energy is given by
    C F S E invisible function application left parenthesis octahedral right parenthesis equals negative 0.4 capital delta subscript 0 end subscript open parentheses t subscript 2 g end subscript close parentheses plus 0.6 capital delta subscript 0 end subscript open parentheses e subscript g end subscript close parentheses

    The CFSE increases the thermodynamic stability of the complexes i.e it affects the actual lattice energy over the theoretically calculated energy that does not take CFSE it into account. In studying tetrahedral complexes a regular tetrahedron is related to a cube. One atom is at the centre and four of eight corners are occupied by the ligands. The directions of x comma y comma z point to the centres of the faces of the cube . The directions of the approach of the ligands does not coincide exactly with the atomic orbitals.
    In these complexes the e subscript g end subscript orbitals are more stable compared to the t subscript 2 g end subscript orbitals.
    In which of the following complex ion, the metal ion will have t subscript 2 g end subscript superscript 6 end superscript e subscript g end subscript superscript 0 end superscript configuration according to CFT:

    In octahedral complexes the filling of t subscript 2 g end subscript orbitals decreases the energy of a complex, that is makes it more stable by negative 0.4 capital delta subscript 0 end subscript per electron. Filling the e subscript g end subscript orbitals increases the energy by plus 0.6 capital delta subscript 0 end subscript per electron. The total crystal field stabilization energy is given by
    C F S E invisible function application left parenthesis octahedral right parenthesis equals negative 0.4 capital delta subscript 0 end subscript open parentheses t subscript 2 g end subscript close parentheses plus 0.6 capital delta subscript 0 end subscript open parentheses e subscript g end subscript close parentheses

    The CFSE increases the thermodynamic stability of the complexes i.e it affects the actual lattice energy over the theoretically calculated energy that does not take CFSE it into account. In studying tetrahedral complexes a regular tetrahedron is related to a cube. One atom is at the centre and four of eight corners are occupied by the ligands. The directions of x comma y comma z point to the centres of the faces of the cube . The directions of the approach of the ligands does not coincide exactly with the atomic orbitals.
    In these complexes the e subscript g end subscript orbitals are more stable compared to the t subscript 2 g end subscript orbitals.
    In which of the following complex ion, the metal ion will have t subscript 2 g end subscript superscript 6 end superscript e subscript g end subscript superscript 0 end superscript configuration according to CFT:

    Chemistry-General
    General
    Chemistry-

    The complexes given below show:

    The complexes given below show:

    Chemistry-General
    General
    Chemistry-

    The correct IUPAC name of the complex:

    The correct IUPAC name of the complex:

    Chemistry-General
    parallel
    General
    Maths-

    Convert mixed fraction into improper fraction. 1 5/6

    Convert mixed fraction into improper fraction. 1 5/6

    Maths-General
    General
    Maths-

    Divide fraction 5/6 divided by 2/5

    Divide fraction 5/6 divided by 2/5

    Maths-General
    General
    Maths-

    Add the fractions. 5/6 + 2/9

    Add the fractions. 5/6 + 2/9

    Maths-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.