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Maths-

General

Easy

Question

The present population of a town is 200000. Its population increases by 10% in the first year and 15% in the second year. Find the population of the town at the end of the two years.

hint Hint:

Use the formula of total amount to find the total population at the end of 2 years.

The correct answer is: 253000

Complete step by step solution:
Present population of the town P = 200000,
We calculate the total population at the end of first year by the formula $A equals P open parentheses 1 plus R over 100 close parentheses to the power of T$ …(i)
Here, we have T = 1 years, P = 200000 ,R = 10% and A = ?
On substituting the known values in (i), we get $A equals 200000 open parentheses 1 plus 10 over 100 close parentheses to the power of 1$
$not stretchy rightwards double arrow A equals 220000$
Hence total population at the end of first year = 220000
So the new population is 220000
Now the formula to find total population at the end of two years = $A equals P open parentheses 1 plus R over 100 close parentheses to the power of T$ …(ii)
Here, we have T = 1 years, P = 220000 , R = 15%(increases) and A = ?
On substituting the known values in (ii), we get $A equals 220000 open parentheses 1 plus 15 over 100 close parentheses to the power of 1$
$not stretchy rightwards double arrow A equals 220000 cross times 1.15 equals 253000$
Hence total population at the end of second year = 253000

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