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Question

The system of equations lambda x plus y plus z equals 0 comma negative x plus lambda y plus z equals 0 comma negative x minus y plus lambda z equals 0, will have a non zero solution if real values of lambdaare given by

  1. 0    
  2. 1    
  3. 3    
  4. square root of 3    

The correct answer is: 0


    Accordingly, open vertical bar table row lambda 1 1 row cell negative 1 end cell lambda 1 row cell negative 1 end cell cell negative 1 end cell lambda end table close vertical bar equals 0 rightwards double arrow lambda to the power of 3 end exponent plus 3 lambda equals 0
    Therefore lambda equals 0, since lambda equals i square root of 3does not exist.

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