The table above shows the number of international tourist arrivals, rounded to the nearest tenth of a million, to the top nine tourist destinations in both 2012 and 2013.

Based on the information given in the table, how much greater, in millions, was the median number of international tourist arrivals to the top nine tourist destinations in 2013 than the median number in 2012, to the nearest tenth of a million?

The correct answer is: 1.3

○        The concept used in the question id of median.
○        Median: Median is the middlemost value of the given data set when data is arranged either in ascending or descending order.
○        For odd number of observations,
Median = term
○        For even number of observations,
Median  = 
Where n is number of observations.

• Step by step explanation:

○        Given:
No of onbervations = 9
 Observations are already in descending order.
○        Step 1:
As no of observations are odd i.e 9
therefore,
Median = term
Median = term
Median = 5^th term
○        Step 2:
For 2012,
5^th term is 46.4
∴  median of 2012 = 46.4
For 2013,
5^th term is 47.7
∴  median of 2013 = 47.7
○        Step 2:
Subtraction of median of 2013 and 2012
 47.7 - 46.4
 1.3
Final Answer:
Hence, median of 2013 is greater than median of 2012 by 1.3