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Question

The value of p for which the straight lines r with rightwards arrow on top equals left parenthesis 2 i with ˆ on top plus 9 j with ˆ on top plus 13 k with ˆ on top right parenthesis plus t left parenthesis i with ˆ on top plus 2 j with ˆ on top plus 3 k with ˆ on top right parenthesis and r with rightwards arrow on top equals left parenthesis negative 3 i with ˆ on top plus 7 j with ˆ on top plus p k with ˆ on top right parenthesis plus s left parenthesis negative i with ˆ on top plus 2 j with ˆ on top minus 3 k with ˆ on top right parenthesis are coplanar is

  1. -1    
  2. 1    
  3. negative 2    
  4. 2    

hintHint:

We are given equation of two straight lines. We are given that the lines are coplanar. Coplanar lines means line containing in the same plane. We have to find the value of p for which the lines are coplanar.

The correct answer is: negative 2


    The given equation of the lines are as follows:
    r with rightwards arrow on top equals left parenthesis 2 i with hat on top space plus space 9 j with hat on top space plus space 13 k with hat on top right parenthesis space plus space t left parenthesis i with hat on top space plus space 2 j with hat on top space plus 3 k with hat on top right parenthesis
r with rightwards arrow on top equals left parenthesis negative 3 i with hat on top space plus space 7 j with hat on top space plus space p k with hat on top right parenthesis space plus space s left parenthesis negative i with hat on top space plus space 2 j space with hat on top plus 3 k with hat on top right parenthesis
    We have to find the value of p such that the lines are coplanar.
    The conditions for coplanarity is as follows:
    If two lines are given by
    table attributes columnalign left end attributes row cell r with rightwards arrow on top equals a with rightwards arrow on top subscript 1 plus beta subscript 1 stack b subscript 1 with rightwards arrow on top end cell row cell r with rightwards arrow on top equals stack a subscript 2 with rightwards arrow on top plus beta subscript 2 stack b subscript 2 with rightwards arrow on top end cell row blank row blank end table
    Here, the first term represents the position vector of a point through which line is passing. Second term is for the vector parallel to the given line.
    The condition for coplanarity is as follows:
    open parentheses a with rightwards arrow on top subscript 1 minus stack a subscript 2 with rightwards arrow on top close parentheses. left parenthesis stack b subscript 1 with rightwards arrow on top space cross times space stack b subscript 2 with rightwards arrow on top right parenthesis space equals space 0
    If we see it is an scalar triple product. So, the scalar triple product should be zero.
    W e space w i l l space f i n d space stack a subscript 1 with rightwards arrow on top minus stack a subscript 2 with rightwards arrow on top space f i r s t. space L e t space u s space d e n o t e space i t space b y space a with rightwards arrow on top
a with rightwards arrow on top space equals space stack space a subscript 1 with rightwards arrow on top space minus space stack a subscript 2 with rightwards arrow on top space
space space space space equals space 2 i with hat on top space plus space 9 j with hat on top space plus space 13 k with hat on top space minus left parenthesis negative 3 i with hat on top plus space 7 j with dot on top space plus space p k with hat on top right parenthesis
space space space space equals left parenthesis 2 plus 3 right parenthesis i with hat on top space plus left parenthesis 9 minus 7 right parenthesis j with hat on top space plus left parenthesis 13 minus p right parenthesis k with hat on top
space space space space equals 5 i with hat on top space plus 2 j with hat on top plus left parenthesis 13 space minus space p right parenthesis k with hat on top
    We will solve the scalar triple product now.
    a with rightwards arrow on top. left parenthesis stack b subscript 1 with rightwards arrow on top cross times stack b subscript 2 with rightwards arrow on top right parenthesis space equals open vertical bar table row 5 2 cell 13 minus p end cell row 1 2 3 row cell negative 1 end cell 2 cell negative 3 end cell end table close vertical bar
space space space space space space space space space space space space space space space space space 0 equals 5 left parenthesis negative 6 minus 6 right parenthesis minus 2 left square bracket left parenthesis negative 3 right parenthesis space minus left parenthesis negative 3 right parenthesis right square bracket plus left parenthesis 13 minus p right parenthesis left square bracket 2 minus left parenthesis negative 2 right parenthesis right square bracket
space space space space space space space space space space space space space space space space space 0 equals negative 60 space plus space 0 space plus left parenthesis 13 space minus p right parenthesis 4
space space space space space space space space space space space space space space space space space 0 equals negative 60 space plus 52 space minus 4 p
space space space space space space space space space space space space space space space space space 0 space equals space minus 8 space minus 4 p
R e a r r a n g e space t h e space e q u a t i o n
space space space space space minus 8 space minus 4 p space equals 0
A d d space 8 space t o space b o t h space t h e space s i d e s
space space space space space space space space space space space space minus 4 p space equals 8
space space space space space space space space space space space space space space space space space space p space equals negative 2


space space space space space space space space space space space space space space space space space space space space
    So, the value of p for which the lines are coplanar is -2.

    For such questions, we should know the condition for two lines to be coplanar. We should also know about the scalar triple product.

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