Physics
Grade-8
Easy

Question

A 3,000 kg truck moving at +10 fraction numerator m over denominator s end fraction hits a 1,000 kg parked car which moves off at +15 fraction numerator m over denominator s end fraction. What is the velocity of the truck?

  1. 5 fraction numerator m over denominator s end fraction    
  2. 50 fraction numerator m over denominator s end fraction    
  3. 2 fraction numerator m over denominator s end fraction    
  4. 0.2 fraction numerator m over denominator s end fraction    

hintHint:

The formula for the law of conservation of momentum is: m 1 u 1 + m 2 u 2 = m 1 v 1 + m 2 v 2.

The correct answer is: 5 fraction numerator m over denominator s end fraction


    •  The formula for the law of conservation of momentum is: m 1 u 1 + m 2 u 2 = m 1 v 1 + m 2 v 2.
    • parked car means u2=0 
    • let velocity of truck is v1 
    • 3000 cross times 10 plus 1000 cross times 0 equals 1000 cross times 15 plus 3000 v 1
30000 minus 15000 equals 3000 v 1
15000 equals 3000 v 1
v 1 equals 5 space m divided by s

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