Physics-
General
Easy

Question

A body of 2 kg has an initial speed 5ms–1. A force acts on it for some time in the direction of motion. The force time graph is shown in figure. The final speed of the body.

  1. 9.25 m s to the power of negative 1 end exponent    
  2. 5 m s to the power of negative 1 end exponent    
  3. 14.25 ms–1    
  4. 4.25 ms–1    

The correct answer is: 14.25 ms–1


    Impulse = Change in momentum equals m left parenthesis v subscript 2 end subscript minus v subscript 1 end subscript right parenthesis (i)
    1 Again impulse = Area between the graph and time axis
    equals fraction numerator 1 over denominator 2 end fraction cross times 2 cross times 4 plus 2 cross times 4 plus fraction numerator 1 over denominator 2 end fraction left parenthesis 4 plus 2.5 right parenthesis cross times 0.5 plus 2 cross times 2.5
    equals 4 plus 8 plus 1.625 plus 5 equals 18.625...(ii)
    From (i) and (ii), m left parenthesis v subscript 2 end subscript minus v subscript 1 end subscript right parenthesis equals 18.625
    Þv subscript 2 end subscript equals fraction numerator 18.625 over denominator m end fraction plus v subscript 1 end subscript equals fraction numerator 18.625 over denominator 2 end fraction plus 5 equals 14.25   m divided by s

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