Physics
Grade-9
Easy

Question

A cyclist puts 600 J of work on his bicycle and the bicycle gives out 140 J of useful work. Calculate the energy efficiency of the cyclist.

  1. 42%
  2. 23.33 %
  3. 50%
  4. 100%

hintHint:

  • Energy input = useful energy output + waste energy
  • Efficiency (%) = (useful energy output ÷ energy input) × 100

The correct answer is: 23.33 %


    • Energy input = useful energy output + waste energy
    • Here useful energy =140 J
    • Input Energy =600 J
    • Efficiency (%) = (useful energy output ÷ energy input) × 100
    • So Efficiency = 140 over 600 cross times 100 equals 23.33 space percent sign

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