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Question

An electron changes its position from orbit n equals 4 to the orbit n equals 2 of an atom. The wavelength of the emitted radiation’s is (R = Rydberg’s constant)

  1. fraction numerator 16 over denominator R end fraction    
  2. fraction numerator 16 over denominator 3 R end fraction    
  3. fraction numerator 16 over denominator 5 R end fraction    
  4. fraction numerator 16 over denominator 7 R end fraction    

The correct answer is: fraction numerator 16 over denominator 3 R end fraction


    fraction numerator 1 over denominator lambda end fraction equals R open square brackets fraction numerator 1 over denominator n subscript 1 end subscript superscript 2 end superscript end fraction minus fraction numerator 1 over denominator n subscript 2 end subscript superscript 2 end superscript end fraction close square brackets equals R open square brackets fraction numerator 1 over denominator left parenthesis 2 right parenthesis to the power of 2 end exponent end fraction minus fraction numerator 1 over denominator left parenthesis 4 right parenthesis to the power of 2 end exponent end fraction close square brackets Þ lambda equals fraction numerator 16 over denominator 3 R end fraction

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