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Easy

Question

Find the magnetic field at P due to the arrangement shown

  1. fraction numerator mu subscript 0 end subscript i over denominator square root of 2 pi d end fraction open parentheses 1 minus fraction numerator 1 over denominator square root of 2 end fraction close parentheses circled times    
  2. fraction numerator 2 mu subscript 0 end subscript i over denominator square root of 2 pi d end fraction circled times    
  3. fraction numerator mu subscript 0 end subscript i over denominator square root of 2 pi d end fraction circled times    
  4. fraction numerator mu subscript 0 end subscript i over denominator square root of 2 pi d end fraction open parentheses 1 plus fraction numerator 1 over denominator square root of 2 end fraction close parentheses circled times    

The correct answer is: fraction numerator mu subscript 0 end subscript i over denominator square root of 2 pi d end fraction open parentheses 1 minus fraction numerator 1 over denominator square root of 2 end fraction close parentheses circled times

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