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Physics

Grade-9

Easy

Question

In a simple pendulum, the period of oscillation T is related to the length of the pendulum l as:

$\frac{l^{2}}{T} = c o n s \tan t$
$\frac{l}{T} = c o n s \tan t$
$\frac{l^{2}}{T^{2}} = c o n s \tan t$
$\frac{l}{T^{2}} = c o n s \tan t$

hint Hint:

The time period T of a simple pendulum is directly proportional to the square root of length l of the pendulum

The correct answer is: $l over T squared equals c o n s tan t$

$T equals 2 pi square root of l over g end root T squared equals l s o space l over T squared equals c o n s tan t$

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