Physics-
General
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Question

Light of two different frequencies whose photons have energies 1 e V and 2.5 e V respectively, successively illuminates a metal of work function 0.5 e V. The ratio of maximum kinetic energy of the emitted electron will be

  1. 1 : 5    
  2. 1 : 4    
  3. 1 : 2    
  4. 1 : 1    

The correct answer is: 1 : 4


    By usingE equals W subscript 0 end subscript plus K subscript m a x end subscript rightwards double arrow K 0 subscript m a x end subscript
    Hence, K subscript 1 end subscript equals 1 minus 0.5 equals 0.5
    and K subscript 2 end subscript equals 2.5 minus 0.5 equals 2 rightwards double arrow fraction numerator K subscript 1 end subscript over denominator K subscript 2 end subscript end fraction equals fraction numerator 1 over denominator 4 end fraction.

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