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Physics

Grade-10

Easy

Question

Mathematically represent “The sum of momenta of the two objects before collision is equal to the sum of momenta after the collision provided there is no external unbalanced force acting on them.

$m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$
$m_{1} v_{1} + m_{2} u_{2} = m_{1} u_{1} + m_{2} v_{2}$
$m_{1} u_{1} + m_{1} v_{1} = m_{2} v_{2} + m_{2} u_{2}$
$v_{1} u_{1} + v_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2} + m_{1} u_{1} + m_{2} u_{2}$

hint Hint:

According to law of conservation of momentum, initial and final momenta of two bodies before and after collision remains constant in an isolated system.

The correct answer is: $m subscript 1 u subscript 1 plus m subscript 2 u subscript 2 equals m subscript 1 v subscript 1 plus m subscript 2 v subscript 2$

Here, m1= mass of first body, u1= initial velocity of first body; m2= mass of second body, u2= initial velocity of second body and v1= final velocity of first body, v2= final velocity of second body. According to law of conservation of momentum, sum of initial and final momenta are same provided there is no external unbalanced force acting on them.

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