Physics
Grade-9
Easy

Question

Resistors of resistances 10 Ω, 20 Ω, 30 Ω are connected in parallel so that the combination carries a current of 11 A. Potential difference across the combination is

  1. 60 V
  2. 30 V
  3. 120 V
  4. 6 V

hintHint:

When the resistors are connected in parallel, the resistance can be calculated as-  1 over R subscript T equals 1 over R subscript 1 plus 1 over R subscript 2 plus 1 over R subscript 3 and potential difference across all the resistors is the same.

And we can calculate potential difference using Ohm's law, V=IR

The correct answer is: 60 V


    When the resistors of resistances 10 Ω, 20 Ω, and 30 Ω are connected in parallel and the combination carries a current of 11 A, the potential difference across the combination is 60V.
    • The potential difference in a parallel combination of resistors is the sum of all the resistances.
    • The resistances of the parallel combination are 10Ω, 20Ω, and 30Ω, and the combination of all can give the potential difference.
    • R= 5.45 Ω
    • Applying Ohm's law, V= IR, 5.45 cross times 11 equals space 60 space V

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