Physics-
General
Easy

Question

The de-Broglie wavelength of a neutron at 27°C is lambda. What will be its wavelength at 927°C

  1. lambda / 2    
  2. lambda / 3    
  3. lambda / 4    
  4. lambda / 9    

The correct answer is: lambda / 2


    lambda subscript n e u t r o n end subscript proportional to fraction numerator 1 over denominator square root of T end fraction Þ fraction numerator lambda subscript 1 end subscript over denominator lambda subscript 2 end subscript end fraction equals square root of fraction numerator T subscript 2 end subscript over denominator T subscript 1 end subscript end fraction end root
    Þfraction numerator lambda over denominator lambda subscript 2 end subscript end fraction equals square root of fraction numerator left parenthesis 273 plus 927 right parenthesis over denominator left parenthesis 273 plus 27 right parenthesis end fraction end root equals square root of fraction numerator 1200 over denominator 300 end fraction end root equals 2 Þlambda subscript 2 end subscript equals fraction numerator lambda over denominator 2 end fraction.

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