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Physics

Grade-8

Easy

Question

There are two cars, car A and car B. Mass of car A is 10000 kg, travelling at 30 $fraction numerator m over denominator s end fraction$ collide with car B of mass 30000 kg travelling at 20 $fraction numerator m over denominator s end fraction$ in same direction. After collision, the velocity of car A becomes 40 $fraction numerator m over denominator s end fraction$ . Calculate the velocity of car B after the collision?

$\frac{50}{3}$ $\frac{m}{s}$
$\frac{50}{3}$ $\frac{m}{s}$
$\frac{53}{3}$ $\frac{m}{s}$
$\frac{47}{3}$ $\frac{m}{s}$

Hint:

The formula for the law of conservation of momentum is: m 1 u 1 + m 2 u 2 = m 1 v 1 + m 2 v 2.

The correct answer is: $fraction numerator 50 over denominator 3 end fraction$ $fraction numerator m over denominator s end fraction$

The formula for the law of conservation of momentum is: m 1 u 1 + m 2 u 2 = m 1 v 1 + m 2 v 2.
$10000 cross times 30 plus 30000 cross times 20 equals 10000 cross times 40 plus 30000 cross times v 2 v 2 equals 50 over 3 m divided by s$

Related Questions to study

There are two cars, car A and car B. Mass of car A is 2000 kg, travelling at 30 $fraction numerator m over denominator s end fraction$ collide with car B of mass 3000 kg travelling at 40 $fraction numerator m over denominator s end fraction$ in same direction. After collision, the velocity of car A becomes 50 $fraction numerator m over denominator s end fraction$ . Calculate the velocity of car B after the collision?

$\frac{80}{3} \frac{m}{s}$
$\frac{3}{80}$ $\frac{m}{s}$
$\frac{83}{3}$ $\frac{m}{s}$
$\frac{77}{3}$ $\frac{m}{s}$

There are two cars, car A and car B. Mass of car A is 2000 kg, travelling at 30 $fraction numerator m over denominator s end fraction$ collide with car B of mass 3000 kg travelling at 40 $fraction numerator m over denominator s end fraction$ in same direction. After collision, the velocity of car A becomes 50 $fraction numerator m over denominator s end fraction$ . Calculate the velocity of car B after the collision?

$\frac{80}{3} \frac{m}{s}$
$\frac{3}{80}$ $\frac{m}{s}$
$\frac{83}{3}$ $\frac{m}{s}$
$\frac{77}{3}$ $\frac{m}{s}$

A 3,000 kg truck moving at +10 $fraction numerator m over denominator s end fraction$ hits a 1,000 kg parked car which moves off at +15 $fraction numerator m over denominator s end fraction$ . What is the velocity of the truck?

5 $\frac{m}{s}$
50 $\frac{m}{s}$
2 $\frac{m}{s}$
0.2 $\frac{m}{s}$

A 3,000 kg truck moving at +10 $fraction numerator m over denominator s end fraction$ hits a 1,000 kg parked car which moves off at +15 $fraction numerator m over denominator s end fraction$ . What is the velocity of the truck?

5 $\frac{m}{s}$
50 $\frac{m}{s}$
2 $\frac{m}{s}$
0.2 $\frac{m}{s}$

The following example follows law of conservation of momentum. Is the statement true or false?

True
False

The following example follows law of conservation of momentum. Is the statement true or false?

True
False

parallel

The following example follows law of conservation of momentum. Is the statement true or false?

True
False

The following example follows law of conservation of momentum. Is the statement true or false?

True
False

The following example follows law of conservation of momentum. Is the statement true or false?

True
False

The following example follows law of conservation of momentum. Is the statement true or false?

True
False

The following example follows law of conservation of momentum. Is the statement true or false?

True
False

The following example follows law of conservation of momentum. Is the statement true or false?

True
False

parallel

The total momentum before a collision is ____ the total momentum after a collision

Equal to
Less than
More than
Cannot say

The total momentum before a collision is ____ the total momentum after a collision

Equal to
Less than
More than
Cannot say

Law of conservation of momentum states that

The sum of momenta of the two objects before collision is equal to the sum of momenta after the collision provided there is no external unbalanced force acting on them
Magnitude of the final momenta = magnitude of the initial moment.
$m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$
All the above

Law of conservation of momentum states that

The sum of momenta of the two objects before collision is equal to the sum of momenta after the collision provided there is no external unbalanced force acting on them
Magnitude of the final momenta = magnitude of the initial moment.
$m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$
All the above

What can you say about the numerical data from the figure, in connection with the conservation of linear momentum?

It is conserved
Before collision > after collision
After collision > before collision
Cannot say

What can you say about the numerical data from the figure, in connection with the conservation of linear momentum?

It is conserved
Before collision > after collision
After collision > before collision
Cannot say

parallel

What is the momentum of car after collision?

50,000 $\frac{k g m}{s}$
5,000 $\frac{k g m}{s}$
500 $\frac{k g m}{s}$
0 $\frac{k g m}{s}$

What is the momentum of car after collision?

50,000 $\frac{k g m}{s}$
5,000 $\frac{k g m}{s}$
500 $\frac{k g m}{s}$
0 $\frac{k g m}{s}$

What is the momentum of truck before collision?

3000 $\frac{k g m}{s}$
300 $\frac{k g m}{s}$
30 $\frac{k g m}{s}$
0 $\frac{k g m}{s}$

What is the momentum of truck before collision?

3000 $\frac{k g m}{s}$
300 $\frac{k g m}{s}$
30 $\frac{k g m}{s}$
0 $\frac{k g m}{s}$

What is the momentum of car before collision?

2,00,000 $\frac{k g m}{s}$
20,000 $\frac{k g m}{s}$
2000 $\frac{k g m}{s}$
200 $\frac{k g m}{s}$

What is the momentum of car before collision?

2,00,000 $\frac{k g m}{s}$
20,000 $\frac{k g m}{s}$
2000 $\frac{k g m}{s}$
200 $\frac{k g m}{s}$

parallel

The following example follows law of conservation of momentum. Is the statement true or false?