Physics
Grade-10
Easy
Question
There are two cars, car A and car B. Mass of car A is 3000 kg, travelling at 40 m/s collide with car B of mass 4000 kg travelling at 20 m/s in same direction. After collision, the velocity of car A becomes 50 m/s. Calculate the velocity of car B after the collision?
- 12 m/s
- 12.5 m/s
- 13 m/s
- 14 m/s
Hint:
Use the law of conservation of momentum.
The correct answer is: 12.5 m/s
Given that-
Mass of car A = 3000 Kg
Speed of car A = 40 m/s
Mass of car B = 4000 Kg
Speed of the car B = 20 m/s
Final speed of car A = 50 m/s
Let the final speed of car B = v m/s
Using the law of conservation of momentum,
(3000 x 40) + (4000 x 20) = (3000 x 50) + (4000 x v)
1,20,000 + 80,000 = 150000 + 4000v
50000 = 4000 v
v = 50000/4000 = 12.5 m/s
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Final:
Mass of the blue ball is 0.43 Kg and mass of the pink ball is 0.45 kg
The following example follows the law of conservation of momentum. Is the statement true or false?
Initial:
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