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Physics

General

Easy

Question

A and $straight B with rightwards arrow on top$ are nonzero vectors. Which from the followings is true?

$| \vec{A} + \bar{B} |^{2} - | \vec{A} - \bar{B} |^{2} = 2 (A^{2} + B^{2})$
$| \vec{A} + \vec{B} |^{2} - | \vec{A} - \vec{B} |^{2} = 2 (A^{2} - B^{2})$
$| \vec{A} + \bar{B} |^{2} - | \vec{A} - \vec{B} |^{2} = A^{2} + B^{2}$
$| \vec{A} + \vec{B} |^{2} - | \bar{A} - \bar{B} |^{2} = A^{2} - B^{2}$

The correct answer is: $vertical line A with not stretchy rightwards arrow on top plus B with not stretchy bar on top vertical line squared minus vertical line A with not stretchy rightwards arrow on top minus B with not stretchy bar on top vertical line squared equals 2 open parentheses A squared plus B squared close parentheses$

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