General
Easy
Physics

A block B. placed on a horizontal surface is pulled with initial velocity V. If the coefficient of kinetic friction between surface and block is µ . than after bons much time, block will come to rest ?

PhysicsGeneral

  1. v over g
  2. v over g
  3. g over v
  4. g over v

    Answer:The correct answer is: v over g

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    Extensional of wire 2 cross times 10 to the power of negative 9 end exponent m
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    I. The value of Young’s Modulus is 10 to the power of 11 end exponent N blank m to the power of negative 2 end exponent
    II. The strain is 10 to the power of negative 3 end exponent
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    Stress = fraction numerator 100 N over denominator 10 to the power of negative 6 end exponent m to the power of 2 end exponent end fraction equals 10 to the power of 8 end exponent blank N m to the power of negative 2 end exponent
    Strain equals blank fraction numerator 2 cross times 10 to the power of negative 3 end exponent over denominator 2 end fraction equals 10 to the power of negative 3 end exponent
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    = 10minus1H = 0.1J

    The following data were obtained when a wire was stretched within the elastic region Force applied to wire 100 N
    Area of cross-section of wire 10 to the power of negative 6 end exponent m to the power of 2 end exponent
    Extensional of wire 2 cross times 10 to the power of negative 9 end exponent m
    Which of the following deductions can be correctly made from this data?
    I. The value of Young’s Modulus is 10 to the power of 11 end exponent N blank m to the power of negative 2 end exponent
    II. The strain is 10 to the power of negative 3 end exponent
    III. The energy stored in the wire when the load is applied is 10 J

    physics-General
    Stress = fraction numerator 100 N over denominator 10 to the power of negative 6 end exponent m to the power of 2 end exponent end fraction equals 10 to the power of 8 end exponent blank N m to the power of negative 2 end exponent
    Strain equals blank fraction numerator 2 cross times 10 to the power of negative 3 end exponent over denominator 2 end fraction equals 10 to the power of negative 3 end exponent
    Young modulus
    = fraction numerator 10 to the power of 8 end exponent over denominator 10 to the power of negative 3 end exponent end fraction blank N m to the power of negative 2 end exponent equals 10 to the power of 11 end exponent blank N m to the power of negative 2 end exponent
    Energy stored = fraction numerator 1 over denominator 2 end fraction cross times 100 blank cross times 2 cross times 10 to the power of negative 3 end exponent blank J
    = 10minus1H = 0.1J