Maths-
General
Easy

Question

A contractor can complete a certain piece of work in 9 days. He employed a certain number of men, but 6 of them are absent from the very first day, the rest could finish the work in 15 days. How many men were originally employed?

hintHint:

Hint:
When two quantities of different units are compared and expressed as a ratio, it is known as Rate. For example, a car travels at a speed of 100 kilometres per hour, then it means in one hour it covers 100 kilometres.

The correct answer is: 15 workers


    Let’s say that the total work can be represented as W and let’s say the number of workers who completes the work in 9 days is x. It is given that 6 workers left on the very first day and the rest could finish the work in 15 days or we can say x - 6 workers can finish the work in 15 days.
    Step 1 of 2:
    Work done by x workers in 9 days = W
    Work done by x workers in 1 day = w over g
    Work done by 1 worker in 1 day = fraction numerator W over denominator 9 x end fraction
    Step 2 of 2:
    Work done by x-6 workers in 1 day = fraction numerator W over denominator 9 x end fraction cross times left parenthesis x minus 6 right parenthesis
    Work done by x-6 workers in 15 days = fraction numerator W over denominator 9 x end fraction cross times left parenthesis x minus 6 right parenthesis cross times 15
    Also, Work done by x - 6 workers in 15 days = W
    So, fraction numerator W over denominator 9 x end fraction cross times left parenthesis x minus 6 right parenthesis cross times 15 = W
    15x - 90 = 9x
    6x = 90
    x = 15 workers
    Final Answer:
    Hence, 15 men were originally employed

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