Maths-
General
Easy

Question

A ground in a shape of a parallelogram needs to be fenced by a wire. The one side of the parallelogram is 8 inches and the area of ground is 120 sq. inches respectively.
Find the minimum length of wire needed for the work.

hintHint:

ground is in the shape of parallelogram ,
The area of parallelogram can be given as l b sin theta where l and b are side lengths of
parallelogram where theta is the angle between l and b .

The correct answer is: Min value of b = 15 inches


    Ans :- 15 m .
    Explanation :-
    Given , l equals 8 text  inches  end text
    Area = 120 sq. inches
    l b sin invisible function application theta equals 120 not stretchy rightwards double arrow 8 b sin invisible function application theta equals 120 not stretchy rightwards double arrow b equals fraction numerator 15 over denominator sin invisible function application theta end fraction
    b element of left square bracket 15 comma straight infinity right parenthesis
    Min value of b = 15 inches to get minimum wire for fencing .

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