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A particle is moving along the circle x squared plus y squared equals a squared in anticlockwise direction. The x–y plane is a rough horizontal stationary surface. At the point left parenthesis a space cos theta comma space a space sin theta right parenthesis, the unit vector in the direction of friction on the particle is

  1. cos space theta i space plus sin space theta j space
  2. negative left parenthesis cos space theta i space plus sin space theta j space right parenthesis
  3. sin space theta i space minus cos space theta j space
  4. cos space theta i space ⃗ minus sin space theta j space

The correct answer is: sin space theta i space minus cos space theta j space

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