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A particle is thrown in upward direction with Velocity V0 It passes through a point p of height h at time t1 and t2 so t1+t1

  1. v subscript o over g
  2. fraction numerator 2 v subscript 0 over denominator g end fraction
  3. fraction numerator 2 h over denominator g end fraction
  4. fraction numerator h over denominator 2 g end fraction

The correct answer is: fraction numerator 2 v subscript 0 over denominator g end fraction

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The function f colon R not stretchy rightwards arrow R text  defined by  end text f left parenthesis x right parenthesis equals x minus left square bracket x right square bracket comma straight for all x element of R text  is  end text

The function f colon R not stretchy rightwards arrow R text  defined by  end text f left parenthesis x right parenthesis equals x minus left square bracket x right square bracket comma straight for all x element of R text  is  end text

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A sphere of radius ‘R’ floats in a liquid of density ‘s’ such that its diameter x-x is below distance ‘h’ from free surface as shown. The density of sphere is r. The sphere is depressed slightly and released. The frequency of small oscillation is

negative pi left parenthesis R to the power of 2 end exponent minus h to the power of 2 end exponent right parenthesis times left parenthesis x right parenthesis times sigma times g equals fraction numerator 4 pi R to the power of 3 end exponent rho left parenthesis a right parenthesis over denominator 3 end fraction
and a equals negative omega to the power of 2 end exponent left parenthesis x right parenthesis

A sphere of radius ‘R’ floats in a liquid of density ‘s’ such that its diameter x-x is below distance ‘h’ from free surface as shown. The density of sphere is r. The sphere is depressed slightly and released. The frequency of small oscillation is

physics-General
negative pi left parenthesis R to the power of 2 end exponent minus h to the power of 2 end exponent right parenthesis times left parenthesis x right parenthesis times sigma times g equals fraction numerator 4 pi R to the power of 3 end exponent rho left parenthesis a right parenthesis over denominator 3 end fraction
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A conical flask of mass 10 kg and base area as 103 cm2 is floating in liquid of relative density 1.2, as shown in the figure. The force that liquid exerts on curved surface of conical flask will be (Given g = 10 m/s2)


= Buoyant force = weight
F = 20 N in down ward direction

A conical flask of mass 10 kg and base area as 103 cm2 is floating in liquid of relative density 1.2, as shown in the figure. The force that liquid exerts on curved surface of conical flask will be (Given g = 10 m/s2)

Physics-General

= Buoyant force = weight
F = 20 N in down ward direction
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A vertical jet of water coming out of a nozzle with velocity 20 m/s supports a plate of mass M stationary at a height h = 15m, as shown in the figure. If the rate of water flow is 1 litre per second, the mass of the plate is (Assume the collision to be inelastic).

Force by liquid = Mg

But and

A vertical jet of water coming out of a nozzle with velocity 20 m/s supports a plate of mass M stationary at a height h = 15m, as shown in the figure. If the rate of water flow is 1 litre per second, the mass of the plate is (Assume the collision to be inelastic).

Physics-General
Force by liquid = Mg

But and

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A thin movable plate is separated from two fixed plates P subscript 1 and P subscript 2 by two highly viscous liquids of coefficients of viscosity n subscript 1 and n subscript 2 as shown, where n subscript 2 end subscript equals 9 n subscript 1 end subscript. Area of contact of movable plate with each fluid is same. If the distance between two fixed plates is ‘h’, then the distance ‘h subscript 1 end subscript’ of movable plate from upper plate such that movable plate can be moved with a finite velocity by applying the minimum possible force on movable plate is ( assume only linear velocity distribution in each liquid).

Viscous force due to upper liquid equals n subscript 1 end subscript A open parentheses fraction numerator v minus o over denominator h subscript 1 end subscript end fraction close parentheses
Viscous force due to lower liquid = n subscript 2 end subscript A open parentheses fraction numerator v minus o over denominator h minus h subscript 1 end subscript end fraction close parentheses
If total force is minimum
fraction numerator d over denominator d h subscript 1 end subscript end fraction open square brackets fraction numerator n subscript 1 end subscript over denominator h subscript 1 end subscript end fraction plus fraction numerator n subscript 2 end subscript over denominator h minus h subscript 1 end subscript end fraction close square brackets equals 0

A thin movable plate is separated from two fixed plates P subscript 1 and P subscript 2 by two highly viscous liquids of coefficients of viscosity n subscript 1 and n subscript 2 as shown, where n subscript 2 end subscript equals 9 n subscript 1 end subscript. Area of contact of movable plate with each fluid is same. If the distance between two fixed plates is ‘h’, then the distance ‘h subscript 1 end subscript’ of movable plate from upper plate such that movable plate can be moved with a finite velocity by applying the minimum possible force on movable plate is ( assume only linear velocity distribution in each liquid).

physics-General
Viscous force due to upper liquid equals n subscript 1 end subscript A open parentheses fraction numerator v minus o over denominator h subscript 1 end subscript end fraction close parentheses
Viscous force due to lower liquid = n subscript 2 end subscript A open parentheses fraction numerator v minus o over denominator h minus h subscript 1 end subscript end fraction close parentheses
If total force is minimum
fraction numerator d over denominator d h subscript 1 end subscript end fraction open square brackets fraction numerator n subscript 1 end subscript over denominator h subscript 1 end subscript end fraction plus fraction numerator n subscript 2 end subscript over denominator h minus h subscript 1 end subscript end fraction close square brackets equals 0
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Figure shows a stream of fluid emerging from a tube in the base of an open fixed tank. The expression of ‘y’ (Maximum height traveled by jet of water) is

y equals fraction numerator u subscript y end subscript superscript 2 end superscript over denominator 2 g end fraction
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Figure shows a stream of fluid emerging from a tube in the base of an open fixed tank. The expression of ‘y’ (Maximum height traveled by jet of water) is

physics-General
y equals fraction numerator u subscript y end subscript superscript 2 end superscript over denominator 2 g end fraction
u equals square root of 2 g h end root u subscript y end subscript equals square root of 2 g h end root sin invisible function application theta rightwards double arrow y equals fraction numerator open parentheses square root of 2 g h end root sin invisible function application theta close parentheses to the power of 2 end exponent over denominator 2 g end fraction equals h sin to the power of 2 end exponent invisible function application theta
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For the arrangement shown in figure the time interval after which the water jet ceases to cross the wall (area of cross section of tank is A and orifice is ‘a’)

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time taken by liquid to drain out from H to h is equals fraction numerator A over denominator a end fraction square root of fraction numerator 2 over denominator g end fraction end root open square brackets square root of H minus square root of h close square brackets

For the arrangement shown in figure the time interval after which the water jet ceases to cross the wall (area of cross section of tank is A and orifice is ‘a’)

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Velocity of efflux = square root of 2 g h end root
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physicsGeneral
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