Maths-

General

Easy

Question

# A room is 10 m long and 6 m wide. How many tiles of size 20 cm by 10 cm are required to cover its floor?

## The correct answer is: 3,000 tiles would be required to cover the floor of the given room.

### Hint:-

Area of a rectangle = length × breadth

Step-by-step solution:-

Covering the floor of a room with tiles means putting tiles on the whole surface of the room.

∴ If we know the area of the whole room and the area of each tile, we can find the number of tiles required to cover the floor.

Let the number of tiles required be n

Now, from the given information,

length of the room = l1 = 10m

breadth of the room = b^{1} = 6m

length of each tile = l2 = 20 cm = 0.2 m ............................................... (1m = 100 cm. ∴ 20 cm = 20/100 m = 0.2 m)

breadth of each tile = b^{2} = 10 cm = 01. m ............................................ (1m = 100 cm. ∴ 10 cm = 10/100 m = 0.1 m)

∴ Area of the room = length × breadth

∴ Area of the room = 10 × 6

∴ Area of the room = 60 m^{2} ............................................................... (Equation i)

Area of each tile = length × breadth

∴ Area of each tile = 0.2 × 0.1

∴ Area of each tile = 0.02 m2 ............................................................... (Equation ii)

Area of the room = Area of each tile × total number of tiles required.

∴ 60 = 0.02 × total number of tiles required ................... (From Equations i & ii)

∴ 60 / 0.02 = total number of tiles required

∴ 3,000 = total number of tiles required

Step-by-step solution:-

Covering the floor of a room with tiles means putting tiles on the whole surface of the room.

∴ If we know the area of the whole room and the area of each tile, we can find the number of tiles required to cover the floor.

Let the number of tiles required be n

Now, from the given information,

length of the room = l^{1} = 10m

breadth of the room = b^{1} = 6m

length of each tile = l^{2} = 20 cm = 0.2 m ............................................... (1m = 100 cm. ∴ 20 cm = 20/100 m = 0.2 m)

breadth of each tile = b2 = 10 cm = 01. m ............................................ (1m = 100 cm. ∴ 10 cm = 10/100 m = 0.1 m)

∴ Area of the room = length × breadth

∴ Area of the room = 10 × 6

∴ Area of the room = 60 m^{2} ............................................................... (Equation i)

Area of each tile = length × breadth

∴ Area of each tile = 0.2 × 0.1

∴ Area of each tile = 0.02 m^{2} ............................................................... (Equation ii)

Area of the room = Area of each tile × total number of tiles required.

∴ 60 = 0.02 × total number of tiles required ................... (From Equations i & ii)

∴ 60 / 0.02 = total number of tiles required

∴ 3,000 = total number of tiles required

Final Answer:-

∴ 3,000 tiles would be required to cover the floor of the given room.

### Related Questions to study

Maths-

### A Solid is in the form of a right circular cone mounted on a hemisphere. The radius of hemisphere is 3.5 cm and height of the cone is 4 cm . The solid is placed in a cylindrical vessel , full of water , in such a way that the whole solid is submerged in water. If the radius of cylindrical vessel is 5 cm and its height is 10.5 cm . Find the volume of water left in the cylindrical vessel

### A Solid is in the form of a right circular cone mounted on a hemisphere. The radius of hemisphere is 3.5 cm and height of the cone is 4 cm . The solid is placed in a cylindrical vessel , full of water , in such a way that the whole solid is submerged in water. If the radius of cylindrical vessel is 5 cm and its height is 10.5 cm . Find the volume of water left in the cylindrical vessel

Maths-General

Maths-

### A path of uniform width 4m runs around the outside a rectangular field 24m by 18 m.Find the area of the path ?

### A path of uniform width 4m runs around the outside a rectangular field 24m by 18 m.Find the area of the path ?

Maths-General

Maths-

### The perimeter of a rectangle is 28 cm and its length is 8 cm. Find its:

(i) breadth (ii) area

### The perimeter of a rectangle is 28 cm and its length is 8 cm. Find its:

(i) breadth (ii) area

Maths-General

Maths-

### How many square tiles of the side 20 cm will be needed to pave a footpath which is 2 m wide and surrounds a rectangular plot 40 m long and 22 m wide.

### How many square tiles of the side 20 cm will be needed to pave a footpath which is 2 m wide and surrounds a rectangular plot 40 m long and 22 m wide.

Maths-General

Maths-

### A circle has a diameter of 120 metres. Your average walking speed is 4 kilometres per hour. How many minutes will it take you to walk around the boundary of the circle 3 times? Round your answer to the nearest integer.

### A circle has a diameter of 120 metres. Your average walking speed is 4 kilometres per hour. How many minutes will it take you to walk around the boundary of the circle 3 times? Round your answer to the nearest integer.

Maths-General

Maths-

### Find the total area in the given figure.

As per the given diagram, rectangles EFGC is in rectangular shape. However, all sides of rectangles EFGC are equal to 30 units, making it a square.

Although final answer remains the same, we should ideally consider it to be a square and solve accordingly.

### Find the total area in the given figure.

Maths-General

As per the given diagram, rectangles EFGC is in rectangular shape. However, all sides of rectangles EFGC are equal to 30 units, making it a square.

Although final answer remains the same, we should ideally consider it to be a square and solve accordingly.

Maths-

### A rectangular parking lot is 90 yards long and 35 yards wide. It costs about $.45 to pave each square foot of the parking lot with asphalt. About how much will it cost to pave the parking lot?

### A rectangular parking lot is 90 yards long and 35 yards wide. It costs about $.45 to pave each square foot of the parking lot with asphalt. About how much will it cost to pave the parking lot?

Maths-General

Maths-

### A person is standing exactly at the centre of a circle. The distance of the person from the boundary of the circle is 3 ft. Find the area of the circle.

### A person is standing exactly at the centre of a circle. The distance of the person from the boundary of the circle is 3 ft. Find the area of the circle.

Maths-General

Maths-

### The length and breadth of a rectangular plot are in the ratio 3: 1 and its perimeter is 128 m. Find the area of the plot ?

### The length and breadth of a rectangular plot are in the ratio 3: 1 and its perimeter is 128 m. Find the area of the plot ?

Maths-General

Maths-

### Find the cost of fencing a square park with 16 m side if the cost of fencing is $16/m.

### Find the cost of fencing a square park with 16 m side if the cost of fencing is $16/m.

Maths-General

Maths-

### If the area of a triangle is 77 m2 and its height is m, find the length of its base

### If the area of a triangle is 77 m2 and its height is m, find the length of its base

Maths-General

Maths-

### What is the area of a uniform path of width 2m along the outside of a square plot of land of length 20 m?

### What is the area of a uniform path of width 2m along the outside of a square plot of land of length 20 m?

Maths-General

Maths-

### A triangle has an area of 7.65 square feet. What is the area of the triangle in square inches?

### A triangle has an area of 7.65 square feet. What is the area of the triangle in square inches?

Maths-General

Maths-

### A rectangular floor of a room is 18 m long 12 m wide.Find the cost of covering the floor with carpet 6 m wide at Rs 40 per metre.

### A rectangular floor of a room is 18 m long 12 m wide.Find the cost of covering the floor with carpet 6 m wide at Rs 40 per metre.

Maths-General

Maths-

### The diagonal of a square is 4 √2 cm. Find the length of another diagonals if the diagonal of another square whose area is double that of the first square.

### The diagonal of a square is 4 √2 cm. Find the length of another diagonals if the diagonal of another square whose area is double that of the first square.

Maths-General