Action of hno_(2) on ch_(3)nh

General

Easy

Chemistry-

Action of $H N O subscript 2 space o n space C H subscript 3 N H subscript 2$ gives:

Chemistry-General

$C H_{3} O H$
$C H_{3} ∙ O ∙ C H_{3}$
$C H_{3} O — N = O$
Both (b) and (c)

Answer:The correct answer is: Both (b) and (c)

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Action of $H N O subscript 2 space o n space C H subscript 3 N H subscript 2$ gives:

$C H_{3} O H$
$C H_{3} ∙ O ∙ C H_{3}$
$C H_{3} O — N = O$
Both (b) and (c)

Answer:The correct answer is: Both (b) and (c)

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Related Questions to study

Primary alcohols can be obtained from the reaction of the $R M g X$ with:

Primary alcohols can be obtained from the reaction of the $R M g X$ with:

$R long dash C H equals C H subscript 2$ reacts with in presence of $H subscript 2 O subscript 2$ to give:

$R long dash C H equals C H subscript 2$ reacts with in presence of $H subscript 2 O subscript 2$ to give:

$L subscript x not stretchy rightwards arrow 0 end subscript equals fraction numerator tan cubed begin display style space end style x minus sin cubed space x over denominator x cubed end fraction$

$L subscript x not stretchy rightwards arrow 0 end subscript equals fraction numerator tan cubed begin display style space end style x minus sin cubed space x over denominator x cubed end fraction$

$L subscript x not stretchy rightwards arrow 0 end subscript equals fraction numerator sin begin display style space end style open parentheses pi cos squared space x close parentheses over denominator x squared end fraction$ Is equal to

$L subscript x not stretchy rightwards arrow 0 end subscript equals fraction numerator sin begin display style space end style open parentheses pi cos squared space x close parentheses over denominator x squared end fraction$ Is equal to

$L t subscript x plus 0 end subscript fraction numerator left parenthesis 1 minus cos space 2 x right parenthesis left parenthesis 3 plus cos space x right parenthesis over denominator x tan space 4 x end fraction$ is equal to

$L t subscript x plus 0 end subscript fraction numerator left parenthesis 1 minus cos space 2 x right parenthesis left parenthesis 3 plus cos space x right parenthesis over denominator x tan space 4 x end fraction$ is equal to

$Lt subscript x not stretchy rightwards arrow 0 end subscript space fraction numerator tan begin display style space end style x minus sin space x over denominator x squared end fraction equals$

$Lt subscript x not stretchy rightwards arrow 0 end subscript space fraction numerator tan begin display style space end style x minus sin space x over denominator x squared end fraction equals$

$Lt subscript x not stretchy rightwards arrow 8 end subscript space fraction numerator square root of 1 plus square root of 1 plus x end root end root minus 2 over denominator x minus 8 end fraction equals$

$Lt subscript x not stretchy rightwards arrow 8 end subscript space fraction numerator square root of 1 plus square root of 1 plus x end root end root minus 2 over denominator x minus 8 end fraction equals$

$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator x over denominator square root of x plus 4 end root minus 2 end fraction equals$

$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator x over denominator square root of x plus 4 end root minus 2 end fraction equals$

$Lt subscript x not stretchy rightwards arrow 0 end subscript fraction numerator cube root of 1 plus x end root minus cube root of 1 minus x end root over denominator x end fraction equals$

$Lt subscript x not stretchy rightwards arrow 0 end subscript fraction numerator cube root of 1 plus x end root minus cube root of 1 minus x end root over denominator x end fraction equals$

$L t subscript x not stretchy rightwards arrow 2 end subscript open parentheses fraction numerator square root of 1 minus cos space left curly bracket 2 left parenthesis x minus 2 right parenthesis factorial end root over denominator x minus 2 end fraction close parentheses equals$

$L t subscript x not stretchy rightwards arrow 2 end subscript open parentheses fraction numerator square root of 1 minus cos space left curly bracket 2 left parenthesis x minus 2 right parenthesis factorial end root over denominator x minus 2 end fraction close parentheses equals$

If $L t subscript x not stretchy rightwards arrow straight infinity end subscript open parentheses 1 plus a over x plus b over x squared close parentheses to the power of 2 x end exponent equals e squared$ then the values of a and b are

If $L t subscript x not stretchy rightwards arrow straight infinity end subscript open parentheses 1 plus a over x plus b over x squared close parentheses to the power of 2 x end exponent equals e squared$ then the values of a and b are

$text In end text straight triangle A B C comma straight capital sigma fraction numerator a squared sin invisible function application left parenthesis B minus C right parenthesis over denominator sin invisible function application A end fraction equals$

$text In end text straight triangle A B C comma straight capital sigma fraction numerator a squared sin invisible function application left parenthesis B minus C right parenthesis over denominator sin invisible function application A end fraction equals$

If $L straight t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator log begin display style space end style left parenthesis 3 plus x right parenthesis minus log space left parenthesis 3 minus x right parenthesis over denominator x end fraction equals k$ then k=

If $L straight t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator log begin display style space end style left parenthesis 3 plus x right parenthesis minus log space left parenthesis 3 minus x right parenthesis over denominator x end fraction equals k$ then k=

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Action of gives:

Both (b) and (c)

Answer:The correct answer is: Both (b) and (c)

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Related Questions to study

Primary alcohols can be obtained from the reaction of the with:

Primary alcohols can be obtained from the reaction of the with:

reacts with in presence of to give:

reacts with in presence of to give:

The quadratic equation whose roots are I and m where l= is

The quadratic equation whose roots are I and m where l= is

Is equal to

Is equal to

is equal to

is equal to

If

If

If then the values of a and b are

If then the values of a and b are

If then k=

If then k=

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Action of $H N O subscript 2 space o n space C H subscript 3 N H subscript 2$ gives:

$C H_{3} O H$
$C H_{3} ∙ O ∙ C H_{3}$
$C H_{3} O — N = O$
Both (b) and (c)

Primary alcohols can be obtained from the reaction of the $R M g X$ with:

Primary alcohols can be obtained from the reaction of the $R M g X$ with:

$R long dash C H equals C H subscript 2$ reacts with in presence of $H subscript 2 O subscript 2$ to give:

$R long dash C H equals C H subscript 2$ reacts with in presence of $H subscript 2 O subscript 2$ to give:

$L subscript x not stretchy rightwards arrow 0 end subscript equals fraction numerator sin begin display style space end style open parentheses pi cos squared space x close parentheses over denominator x squared end fraction$ Is equal to

$L subscript x not stretchy rightwards arrow 0 end subscript equals fraction numerator sin begin display style space end style open parentheses pi cos squared space x close parentheses over denominator x squared end fraction$ Is equal to

$L t subscript x plus 0 end subscript fraction numerator left parenthesis 1 minus cos space 2 x right parenthesis left parenthesis 3 plus cos space x right parenthesis over denominator x tan space 4 x end fraction$ is equal to

$L t subscript x plus 0 end subscript fraction numerator left parenthesis 1 minus cos space 2 x right parenthesis left parenthesis 3 plus cos space x right parenthesis over denominator x tan space 4 x end fraction$ is equal to

If $L t subscript x not stretchy rightwards arrow straight infinity end subscript open parentheses 1 plus a over x plus b over x squared close parentheses to the power of 2 x end exponent equals e squared$ then the values of a and b are

If $L t subscript x not stretchy rightwards arrow straight infinity end subscript open parentheses 1 plus a over x plus b over x squared close parentheses to the power of 2 x end exponent equals e squared$ then the values of a and b are

If $L straight t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator log begin display style space end style left parenthesis 3 plus x right parenthesis minus log space left parenthesis 3 minus x right parenthesis over denominator x end fraction equals k$ then k=

If $L straight t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator log begin display style space end style left parenthesis 3 plus x right parenthesis minus log space left parenthesis 3 minus x right parenthesis over denominator x end fraction equals k$ then k=