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Maths-

General

Easy

Question

Approximate the following irrational numbers to the nearest whole number. $square root of 28$

hint Hint:

Hint:
For rounding off a number to the nearest whole number, we have to look at the first digit after the decimal point. If this digit is less than 5 i.e. 1, 2, 3 or 4 then we don’t have to do anything, but if the digit is 5 or greater i.e 5, 6, 7, 8, 9 we must round up. For example, the nearest whole number to the number 2.8 is 3 while in the case of 2.45, it will be 2.

The correct answer is: 5

Let’s say x = $square root of 28$
Let’s factorise the number inside the square root i.e 28
$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell 28 equals 2 cross times 2 cross times 7 end cell row cell 28 equals 2 squared cross times 5 end cell end table$
Put the factorised in the square root
$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell x equals square root of 2 squared cross times 7 end root end cell row cell x equals 2 square root of 7 end cell end table$
$square root of 7$ is an irrational number and its approximate value is 2.64575…
$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell x equals 2 cross times 2.64575 horizontal ellipsis end cell row cell x equals 5.29150 horizontal ellipsis end cell end table$
As the digit after the decimal point is 2 which is less than 5. So, the nearest whole number will be 5.
Final Answer:
Hence, the nearest whole number of $square root of 28$ is 5.

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