Chemistry-
General
Easy

Question

Arsine is:

  1. Solid
  2. Liquid
  3. Supersaturate liquid
  4. Gas

The correct answer is: Gas

Related Questions to study

General
maths-

Statement-I : The equation sin(cos x) = cos(sin x) does not possess real roots.

Statement-II : If sin x > 0, then 2 n pi less than x less than left parenthesis 2 n plus 1 right parenthesis comma n element of I

Statement-I : The equation sin(cos x) = cos(sin x) does not possess real roots.

Statement-II : If sin x > 0, then 2 n pi less than x less than left parenthesis 2 n plus 1 right parenthesis comma n element of I

maths-General
General
Maths-

Statement-I : In (0, straight pi), the number of solutions of the equation tan space theta plus tan space 2 theta plus tan space 3 theta equals tan space theta tan space 2 theta tan space 3 theta is two

Statement-II : tan space 6 theta is not defined at theta equals left parenthesis 2 straight n plus 1 right parenthesis pi over 12 comma straight n element of straight I

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, it has 5 solutions, but tanθ &tan3θ are not defined at straight pi over 2straight pi over 6fraction numerator 5 straight pi over denominator 6 end fraction. respectively so it remains only 2.

Statement-I : In (0, straight pi), the number of solutions of the equation tan space theta plus tan space 2 theta plus tan space 3 theta equals tan space theta tan space 2 theta tan space 3 theta is two

Statement-II : tan space 6 theta is not defined at theta equals left parenthesis 2 straight n plus 1 right parenthesis pi over 12 comma straight n element of straight I

Maths-General

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, it has 5 solutions, but tanθ &tan3θ are not defined at straight pi over 2straight pi over 6fraction numerator 5 straight pi over denominator 6 end fraction. respectively so it remains only 2.

General
Maths-

Statement-I : If sin x + cos x = square root of open parentheses y plus 1 over y close parentheses end root comma x element of left square bracket 0 comma pi right square bracket then x equals pi over 4 comma y equals 1

Statement-II : AM ≥ GM

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, Start solving first Statement and try to prove it. Then solve the Statement-II. Always, the AM–GM inequality states that AM ≥ GM.

Statement-I : If sin x + cos x = square root of open parentheses y plus 1 over y close parentheses end root comma x element of left square bracket 0 comma pi right square bracket then x equals pi over 4 comma y equals 1

Statement-II : AM ≥ GM

Maths-General

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, Start solving first Statement and try to prove it. Then solve the Statement-II. Always, the AM–GM inequality states that AM ≥ GM.

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General
Maths-

Statement-I : The number of real solutions of the equation sin x = 2x + 2–x is zero

Statement-II : Since |sin x| ≤ 1

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, -1 ≤ sinx  ≤ 1 for all value, remember that.

Statement-I : The number of real solutions of the equation sin x = 2x + 2–x is zero

Statement-II : Since |sin x| ≤ 1

Maths-General

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, -1 ≤ sinx  ≤ 1 for all value, remember that.

General
maths-

sin squared space x minus cos space 2 x equals 2 minus sin space 2 x if

sin squared space x minus cos space 2 x equals 2 minus sin space 2 x if

maths-General
General
maths-

sin squared space x minus cos space 2 x equals 2 minus sin space 2 x if

sin squared space x minus cos space 2 x equals 2 minus sin space 2 x if

maths-General
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General
maths-

cos space 15 x equals sin space 5 x if

cos space 15 x equals sin space 5 x if

maths-General
General
Maths-

sin space x plus sin space 2 x plus sin space 3 x equals cos space x plus cos space 2 x plus cos space 3 x if

sin space x plus sin space 2 x plus sin space 3 x equals cos space x plus cos space 2 x plus cos space 3 x if

Maths-General
General
Maths-

4 sin to the power of 4 space x plus cos to the power of 4 space x equals 1 if

In this question, we have to find the general solution of x. Here more than one option will correct. Remember the rules for finding the general solution.

4 sin to the power of 4 space x plus cos to the power of 4 space x equals 1 if

Maths-General

In this question, we have to find the general solution of x. Here more than one option will correct. Remember the rules for finding the general solution.

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General
Maths-

Number of ordered pairs (a, x) satisfying the equation sec squared space left parenthesis a plus 2 right parenthesis x plus a squared minus 1 equals 0 semicolon minus pi less than x less than pi is

Number of ordered pairs (a, x) satisfying the equation sec squared space left parenthesis a plus 2 right parenthesis x plus a squared minus 1 equals 0 semicolon minus pi less than x less than pi is

Maths-General
General
Maths-

The general solution of the equation, fraction numerator 1 minus sin space x plus midline horizontal ellipsis comma plus left parenthesis negative 1 right parenthesis to the power of n sin to the power of n space x plus midline horizontal ellipsis straight infinity over denominator 1 plus sin space x plus midline horizontal ellipsis plus sin to the power of n space x plus midline horizontal ellipsis straight infinity end fraction equals fraction numerator 1 minus cos space 2 x over denominator 1 plus cos space 2 x end fraction is :

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The general solution of the equation, fraction numerator 1 minus sin space x plus midline horizontal ellipsis comma plus left parenthesis negative 1 right parenthesis to the power of n sin to the power of n space x plus midline horizontal ellipsis straight infinity over denominator 1 plus sin space x plus midline horizontal ellipsis plus sin to the power of n space x plus midline horizontal ellipsis straight infinity end fraction equals fraction numerator 1 minus cos space 2 x over denominator 1 plus cos space 2 x end fraction is :

Maths-General

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General
Chemistry-

The noble gas used in atomic reactor ,is

The noble gas used in atomic reactor ,is

Chemistry-General
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General
chemistry-

Which compound does not give N H subscript 3 on heating?

Which compound does not give N H subscript 3 on heating?

chemistry-General
General
Maths-

In the interval open square brackets negative pi over 2 comma pi over 2 close square brackets the equation log subscript sin space theta end subscript space left parenthesis cos space 2 theta right parenthesis equals 2 has

In this question, we have to find type of solution, here, we know if log subscript a b equals c then we can take antilog, b = ca, and cos2 θ = 1 – 2 sin2 θ . Remember these terms and find the solution easily.

In the interval open square brackets negative pi over 2 comma pi over 2 close square brackets the equation log subscript sin space theta end subscript space left parenthesis cos space 2 theta right parenthesis equals 2 has

Maths-General

In this question, we have to find type of solution, here, we know if log subscript a b equals c then we can take antilog, b = ca, and cos2 θ = 1 – 2 sin2 θ . Remember these terms and find the solution easily.

General
Maths-

If fraction numerator sin cubed space theta minus cos cubed space theta over denominator sin space theta minus cos space theta end fraction minus fraction numerator cos begin display style space end style theta over denominator square root of open parentheses 1 plus cot squared space theta close parentheses end root end fraction minus 2 tan space theta cot space theta equals negative 1 comma theta element of left square bracket 0 comma 2 pi right square bracket comma,then

In this question, we have to find the where is θ lies. Here, always true for sinx ≥ 0 otherwise it is true for x=0,straight pi over 2,fraction numerator 3 straight pi over denominator 2 end fraction,2π and since we also need x≠straight pi over 2,fraction numerator 3 straight pi over denominator 2 end fraction for tanx and x≠0,2π for cotx all the solutions.

If fraction numerator sin cubed space theta minus cos cubed space theta over denominator sin space theta minus cos space theta end fraction minus fraction numerator cos begin display style space end style theta over denominator square root of open parentheses 1 plus cot squared space theta close parentheses end root end fraction minus 2 tan space theta cot space theta equals negative 1 comma theta element of left square bracket 0 comma 2 pi right square bracket comma,then

Maths-General

In this question, we have to find the where is θ lies. Here, always true for sinx ≥ 0 otherwise it is true for x=0,straight pi over 2,fraction numerator 3 straight pi over denominator 2 end fraction,2π and since we also need x≠straight pi over 2,fraction numerator 3 straight pi over denominator 2 end fraction for tanx and x≠0,2π for cotx all the solutions.

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