Maths-

General

Easy

### Question

#### Assertion (A) :If , then

Reason (R) :

- Both A & R are true and R is correct explanation of A
- Both A & R are true and R is not correct explanation of A
- A is true but R is false
- A is false but R is true

#### The correct answer is: Both A & R are true and R is correct explanation of A

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### Related Questions to study

physics-

A particle is released from a height. At certain height its kinetic energy is three times its potential energy. The height and speed of the particle at that instant are respectively

Velocity at when dropped from where

Or (i)

Potential energy at (ii)

Kinetic energy potential energy

Or (i)

Potential energy at (ii)

Kinetic energy potential energy

A particle is released from a height. At certain height its kinetic energy is three times its potential energy. The height and speed of the particle at that instant are respectively

physics-General

Velocity at when dropped from where

Or (i)

Potential energy at (ii)

Kinetic energy potential energy

Or (i)

Potential energy at (ii)

Kinetic energy potential energy

maths-

#### If x is real, then maximum value of is

#### If x is real, then maximum value of is

maths-General

maths-

#### The value of 'c' of Lagrange's mean value theorem for is

#### The value of 'c' of Lagrange's mean value theorem for is

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#### The value of 'c' of Rolle's mean value theorem for is

#### The value of 'c' of Rolle's mean value theorem for is

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#### The value of 'c' of Rolle's theorem for – on [–1, 1] is

#### The value of 'c' of Rolle's theorem for – on [–1, 1] is

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maths-

#### For in [5, 7]

#### For in [5, 7]

maths-General

maths-

#### The value of 'c' in Lagrange's mean value theorem for in [0, 1] is

#### The value of 'c' in Lagrange's mean value theorem for in [0, 1] is

maths-General

maths-

#### The value of 'c' in Lagrange's mean value theorem for in [0, 2] is

#### The value of 'c' in Lagrange's mean value theorem for in [0, 2] is

maths-General

maths-

#### The equation represents

#### The equation represents

maths-General

maths-

#### The polar equation of the circle whose end points of the diameter are and is

#### The polar equation of the circle whose end points of the diameter are and is

maths-General

maths-

#### The radius of the circle is

#### The radius of the circle is

maths-General

Maths-

#### The adjoining figure shows the graph of Then –

#### The adjoining figure shows the graph of Then –

Maths-General

Maths-

#### Graph of y = ax^{2} + bx + c = 0 is given adjacently. What conclusions can be drawn from this graph –

As we can see from the graph we have a parabola curve and since it is opening in an upward direction. So we can say that a > 0 and

Hence, the option (a) is correct.

Here, we can see that the vertex of the parabola is located in the fourth quadrant , therefore it will be =

On further solving this, we get

Therefore, the option (b) is also correct.

Since, at x=0 , the y intercept will be positive and from this, we can conclude that c < 0 and

Hence, the option (c) will also be correct

On checking all the options, and we can see all options are correct and

Therefore, we conclude that all the options available are correct.

Hence, the option (a) is correct.

Here, we can see that the vertex of the parabola is located in the fourth quadrant , therefore it will be =

On further solving this, we get

Therefore, the option (b) is also correct.

Since, at x=0 , the y intercept will be positive and from this, we can conclude that c < 0 and

Hence, the option (c) will also be correct

On checking all the options, and we can see all options are correct and

Therefore, we conclude that all the options available are correct.

#### Graph of y = ax^{2} + bx + c = 0 is given adjacently. What conclusions can be drawn from this graph –

Maths-General

As we can see from the graph we have a parabola curve and since it is opening in an upward direction. So we can say that a > 0 and

Hence, the option (a) is correct.

Here, we can see that the vertex of the parabola is located in the fourth quadrant , therefore it will be =

On further solving this, we get

Therefore, the option (b) is also correct.

Since, at x=0 , the y intercept will be positive and from this, we can conclude that c < 0 and

Hence, the option (c) will also be correct

On checking all the options, and we can see all options are correct and

Therefore, we conclude that all the options available are correct.

Hence, the option (a) is correct.

Here, we can see that the vertex of the parabola is located in the fourth quadrant , therefore it will be =

On further solving this, we get

Therefore, the option (b) is also correct.

Since, at x=0 , the y intercept will be positive and from this, we can conclude that c < 0 and

Hence, the option (c) will also be correct

On checking all the options, and we can see all options are correct and

Therefore, we conclude that all the options available are correct.

maths-

#### For the quadratic polynomial f (x) = 4x^{2} – 8kx + k, the statements which hold good are

#### For the quadratic polynomial f (x) = 4x^{2} – 8kx + k, the statements which hold good are

maths-General

Maths-

#### The graph of the quadratic polynomial y = ax^{2} + bx + c is as shown in the figure. Then :

Clearly, y = represent a parabola opening downwards. Therefore, a < 0

y = cuts negative y- axis , Putting x = 0 in the given equation

-y = c

y = -c

c < 0

Thus, from the above graph c < 0.

#### The graph of the quadratic polynomial y = ax^{2} + bx + c is as shown in the figure. Then :

Maths-General

Clearly, y = represent a parabola opening downwards. Therefore, a < 0

y = cuts negative y- axis , Putting x = 0 in the given equation

-y = c

y = -c

c < 0

Thus, from the above graph c < 0.