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Chemistry-

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Question

Barium adipate $not stretchy ⟶ with text Dry distillation end text on top left parenthesis straight A right parenthesis not stretchy ⟶ with MeCO subscript 3 straight H on top left parenthesis straight B right parenthesis$ The compound (A) and (B) , respectively, are:

The correct answer is:

Related Questions to study

There are two possible value of A in the solution of the matrix equation $open square brackets table row cell 2 A plus 1 end cell cell negative 5 end cell row cell negative 4 end cell A end table close square brackets to the power of negative 1 end exponent$ $open square brackets table row cell A minus 5 end cell B row cell 2 A minus 2 end cell C end table close square brackets$ = $open square brackets table row 14 D row E F end table close square brackets$ , where A, B, C, D, E, F are real numbers. The absolute value of the difference of these two solutions, is:

There are two possible value of A in the solution of the matrix equation $open square brackets table row cell 2 A plus 1 end cell cell negative 5 end cell row cell negative 4 end cell A end table close square brackets to the power of negative 1 end exponent$ $open square brackets table row cell A minus 5 end cell B row cell 2 A minus 2 end cell C end table close square brackets$ = $open square brackets table row 14 D row E F end table close square brackets$ , where A, B, C, D, E, F are real numbers. The absolute value of the difference of these two solutions, is:

For a given matrix A = $open square brackets table row cell cos invisible function application theta end cell cell negative sin invisible function application theta end cell row cell sin invisible function application theta end cell cell cos invisible function application theta end cell end table close square brackets$ which of the following statement holds good:

For a given matrix A = $open square brackets table row cell cos invisible function application theta end cell cell negative sin invisible function application theta end cell row cell sin invisible function application theta end cell cell cos invisible function application theta end cell end table close square brackets$ which of the following statement holds good:

A and B are two given matrices such that the order of A is 3 × 4, If A'B and BA' are both defined then:

A and B are two given matrices such that the order of A is 3 × 4, If A'B and BA' are both defined then:

parallel

If A is an involuntary matrix given byA = $open square brackets table row 0 1 cell negative 1 end cell row 4 cell negative 3 end cell 4 row 3 cell negative 3 end cell 4 end table close square brackets$ then the inverse of $fraction numerator A over denominator 2 end fraction$ will be

If A is an involuntary matrix given byA = $open square brackets table row 0 1 cell negative 1 end cell row 4 cell negative 3 end cell 4 row 3 cell negative 3 end cell 4 end table close square brackets$ then the inverse of $fraction numerator A over denominator 2 end fraction$ will be

Matrix A = $open square brackets table row x 3 2 row 1 y 4 row 2 2 z end table close square brackets$ , If xyz = 60 and 8x + 4y + 3z = 20, then A(adj A) is equal to:

Matrix A = $open square brackets table row x 3 2 row 1 y 4 row 2 2 z end table close square brackets$ , If xyz = 60 and 8x + 4y + 3z = 20, then A(adj A) is equal to:

Let A = $open square brackets table row 1 0 0 row 2 1 0 row 3 2 1 end table close square brackets$ . If U₁, U₂, U₃ are column matrices satisfying AU₁ = $open square brackets table row 1 row 0 row 0 end table close square brackets$ , AU₂ = $open square brackets table row 2 row 3 row 0 end table close square brackets$ , AU₃ = $open square brackets table row 2 row 3 row 1 end table close square brackets$ and U is 3 × 3 matrix whose columns are U₁, U₂ and U₃. Then |U| =

Let A = $open square brackets table row 1 0 0 row 2 1 0 row 3 2 1 end table close square brackets$ . If U₁, U₂, U₃ are column matrices satisfying AU₁ = $open square brackets table row 1 row 0 row 0 end table close square brackets$ , AU₂ = $open square brackets table row 2 row 3 row 0 end table close square brackets$ , AU₃ = $open square brackets table row 2 row 3 row 1 end table close square brackets$ and U is 3 × 3 matrix whose columns are U₁, U₂ and U₃. Then |U| =

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If the matrix A = $open square brackets table row 8 cell – 6 end cell 2 row cell – 6 end cell 7 cell – 4 end cell row 2 cell – 4 end cell lambda end table close square brackets$ is singular, then λ equal to -

If the matrix A = $open square brackets table row 8 cell – 6 end cell 2 row cell – 6 end cell 7 cell – 4 end cell row 2 cell – 4 end cell lambda end table close square brackets$ is singular, then λ equal to -

If AB = I and B = A' then :

If AB = I and B = A' then :

If A and B are square matrices of same size and |B| $not equal to$ 0, then (B^–1 AB)⁴ =

If A and B are square matrices of same size and |B| $not equal to$ 0, then (B^–1 AB)⁴ =

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If B is non-singular matrix and A is a square matrix of same size, then det (B^–1AB) =

If B is non-singular matrix and A is a square matrix of same size, then det (B^–1AB) =

If A satisfies the equation x³ – 5x² + 4x + k = 0, then A^–1 exists if -

If A satisfies the equation x³ – 5x² + 4x + k = 0, then A^–1 exists if -

If 3A = $open square brackets table row 1 2 2 row 2 1 cell – 2 end cell row x 2 y end table close square brackets$ and A is orthogonal, then x + y =

If 3A = $open square brackets table row 1 2 2 row 2 1 cell – 2 end cell row x 2 y end table close square brackets$ and A is orthogonal, then x + y =

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If A, B are symmetric matrices of the same order then (AB – BA) is -

If A, B are symmetric matrices of the same order then (AB – BA) is -

If A = $open square brackets table row 4 cell x plus 2 end cell row cell 2 x – 3 end cell cell x plus 1 end cell end table close square brackets$ is symmetric, then x =

If A = $open square brackets table row 4 cell x plus 2 end cell row cell 2 x – 3 end cell cell x plus 1 end cell end table close square brackets$ is symmetric, then x =

If the rank of the matrix $open square brackets table row 4 2 cell 1 minus x end cell row 5 k 1 row 6 3 cell 1 plus x end cell end table close square brackets$ is 2 then

If the rank of the matrix $open square brackets table row 4 2 cell 1 minus x end cell row 5 k 1 row 6 3 cell 1 plus x end cell end table close square brackets$ is 2 then

parallel

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