General
Easy
Biology

Identify A to F in the sectional view of a chloroplast showing the different parts

BiologyGeneral

  1. A-Thylakoid, B-Outer membrane, C-Stroma, D-Stroma lamella, E-Granum, F-Inner membrane  
  2. A-Outer membrane, B-Stroma, C-Inner membrane, D-Granum, E-Thylakoid, F-Stroma lamella    
  3. A-Inner membrane, B-Granum, C-Outer membrane, D-Stroma lamella, E-Stroma, F-Thylakoid    
  4. A-Outer membrane, B-Inner membrane, C-Granum, D-Thylakoid, E-Stroma lamella, F-Stroma    

    Answer:The correct answers are: A-Outer membrane, B-Inner membrane, C-Granum, D-Thylakoid, E-Stroma lamella, F-Stroma, A-Thylakoid, B-Outer membrane, C-Stroma, D-Stroma lamella, E-Granum, F-Inner membrane70 S ribosomes are found in prokaryotes, i. e. comma bacteria and blue green algae. The 70 S ribosomes have 2 subunits, i. e., 50 S and 30 S. The ribosomes of mitochondria are smallcomma blank i. e., 55-60 S type, which are comparable to 70 S than 80 S type.

    Book A Free Demo

    +91

    Grade

    Related Questions to study

    General
    biology

    Organelle important in spindle formation during nuclear division is

    DNA multiplication or duplication of DNA takes place by replication. It takes place during S-phase of interphase in cell-cycle

    Organelle important in spindle formation during nuclear division is

    biologyGeneral
    DNA multiplication or duplication of DNA takes place by replication. It takes place during S-phase of interphase in cell-cycle
    General
    biology

    Consider the following statements and choose the correct one

    In protoplasm, fat store in the form oftriglycerides. Polypeptides, polysaccharides and nucleoside are proteins, carbohydrates ad nucleic acid, respectively

    Consider the following statements and choose the correct one

    biologyGeneral
    In protoplasm, fat store in the form oftriglycerides. Polypeptides, polysaccharides and nucleoside are proteins, carbohydrates ad nucleic acid, respectively
    General
    biology

    The backbone of RNA consists of which of the following sugar?

    Each spindle is a bipolar fibrous structure composed mainly of microtubules. The spindle fibres are mainly composed of tubulin protein.

    The backbone of RNA consists of which of the following sugar?

    biologyGeneral
    Each spindle is a bipolar fibrous structure composed mainly of microtubules. The spindle fibres are mainly composed of tubulin protein.
    General
    biology

    A widely accepted, improved model of cell membrane is

    The ability to distinguish different neighbouring cells is important for organism’s function
    Glycolipids are lipids with attached carbohydrate, which acts as recognition sites during cell-cell interaction, as well as sites of attachment in a tissue
    Glycoproteins are often integral membrane proteins and are also important for cell recognition

    A widely accepted, improved model of cell membrane is

    biologyGeneral
    The ability to distinguish different neighbouring cells is important for organism’s function
    Glycolipids are lipids with attached carbohydrate, which acts as recognition sites during cell-cell interaction, as well as sites of attachment in a tissue
    Glycoproteins are often integral membrane proteins and are also important for cell recognition
    General
    biology

    Rough endoplasmic reticulum differs from smooth walled endoplasmic reticulum due to the presence of

    In eukaryotes, DNA is tightly bound to histones which form a DNA protein particle called nucleosome

    Rough endoplasmic reticulum differs from smooth walled endoplasmic reticulum due to the presence of

    biologyGeneral
    In eukaryotes, DNA is tightly bound to histones which form a DNA protein particle called nucleosome
    General
    biology

    Middle lamella is present

    Steps of Gram’s staining technique
    (i) Staining with weak alkaline solution of crystal violet
    (ii) Treatment with 0.5% iodine solution
    (iii) Washing with water
    (iv) Treatment with absolute alcohol/acetone

    Middle lamella is present

    biologyGeneral
    Steps of Gram’s staining technique
    (i) Staining with weak alkaline solution of crystal violet
    (ii) Treatment with 0.5% iodine solution
    (iii) Washing with water
    (iv) Treatment with absolute alcohol/acetone
    General
    biology

    A are granular structures first observed under electron microscope as dense particles by …B… (1953). Here, A and B refer to

    J D Watson and F H C Crick (1953) showed that DNA has a double helical structure with two polynucleotide chains connected by hydrogen bonds and running in opposite directions (antiparallel). The antiparallel strands of a DNA molecule means that the phosphate groups at the start of two DNA strands are in opposite position (pole).

    A are granular structures first observed under electron microscope as dense particles by …B… (1953). Here, A and B refer to

    biologyGeneral
    J D Watson and F H C Crick (1953) showed that DNA has a double helical structure with two polynucleotide chains connected by hydrogen bonds and running in opposite directions (antiparallel). The antiparallel strands of a DNA molecule means that the phosphate groups at the start of two DNA strands are in opposite position (pole).
    General
    biology

    Number of protofilament in microtubule is

    In a DNA molecule, a complete line measures 34 text Å end text times left parenthesis 3.4 times n m right parenthesis with a distance of 3.4 text Å end text times left parenthesis 0.34 n m right parenthesis between two successive base pairs.

    Number of protofilament in microtubule is

    biologyGeneral
    In a DNA molecule, a complete line measures 34 text Å end text times left parenthesis 3.4 times n m right parenthesis with a distance of 3.4 text Å end text times left parenthesis 0.34 n m right parenthesis between two successive base pairs.
    General
    biology

    Ribosomes that occur exclusively in mitochondria is

    In prokaryotes, a nucleus is absent but nucleoid is found which is equivalent to a single chromosome or prochromosome

    Ribosomes that occur exclusively in mitochondria is

    biologyGeneral
    In prokaryotes, a nucleus is absent but nucleoid is found which is equivalent to a single chromosome or prochromosome
    General
    physics-

    The instantaneous velocity of a point B of the given rod of length 0.5 m is 3 m s to the power of negative 1 end exponent in the represented direction. The angular velocity of the rod for minimum velocity of end A is

    If rod is rotated about end A, then vertical component of velocity v subscript perpendicular end subscript of end A will be zero.
    therefore omega equals fraction numerator v cos invisible function application 60 degree over denominator l end fraction equals fraction numerator square root of 3 v over denominator 2 l end fraction
    equals fraction numerator square root of 3 cross times 3 over denominator 2 cross times 0.5 end fraction equals 5.2 blank r a d s to the power of negative 1 end exponent

    The instantaneous velocity of a point B of the given rod of length 0.5 m is 3 m s to the power of negative 1 end exponent in the represented direction. The angular velocity of the rod for minimum velocity of end A is

    physics-General
    If rod is rotated about end A, then vertical component of velocity v subscript perpendicular end subscript of end A will be zero.
    therefore omega equals fraction numerator v cos invisible function application 60 degree over denominator l end fraction equals fraction numerator square root of 3 v over denominator 2 l end fraction
    equals fraction numerator square root of 3 cross times 3 over denominator 2 cross times 0.5 end fraction equals 5.2 blank r a d s to the power of negative 1 end exponent
    General
    physics-

    A T shaped object with dimension shown in the figure, is lying on a smooth floor. A force F is applied at the point P parallel to A B, such that the object has only the translational motion without rotation. Find the location of P with respect to C.

    For translator motion the force should be applied on the centre of mass of the body so we have to calculate the location of centre of mass of T shaped object.
    Let mass of rod A B is m so the mass of rod C D will be 2m.
    Let y subscript 1 end subscript is the centre of mass of rod A B and y subscript 2 end subscript is the centre of mass of rod C D. We can consider that whole mass of the rod is placed at their respective centre of mass i e, mass m is placed at y subscript 1 end subscript and mass 2 m is placed at y subscript 2 end subscript.
    Taking point c at the origin position vector of points y subscript 1 end subscript a n d blank y subscript 2 end subscript can be written as
    r subscript 1 end subscript equals 2 l j comma blank r subscript 2 end subscript equals l j
    and m subscript 1 end subscript equals m a n d m subscript 2 end subscript equals 2 m
    Position vector of centre of mass of the system
    r subscript C M end subscript equals fraction numerator m subscript 1 end subscript r subscript 1 end subscript plus m subscript 2 end subscript r subscript 2 end subscript over denominator m plus m subscript 2 end subscript end fraction equals fraction numerator m 2 l stack j with hat on top plus 2 m l stack j with hat on top over denominator m plus 2 m end fraction equals fraction numerator 4 m l stack j with hat on top over denominator 3 m end fraction equals fraction numerator 4 l stack j with hat on top over denominator 3 end fraction

    A T shaped object with dimension shown in the figure, is lying on a smooth floor. A force F is applied at the point P parallel to A B, such that the object has only the translational motion without rotation. Find the location of P with respect to C.

    physics-General
    For translator motion the force should be applied on the centre of mass of the body so we have to calculate the location of centre of mass of T shaped object.
    Let mass of rod A B is m so the mass of rod C D will be 2m.
    Let y subscript 1 end subscript is the centre of mass of rod A B and y subscript 2 end subscript is the centre of mass of rod C D. We can consider that whole mass of the rod is placed at their respective centre of mass i e, mass m is placed at y subscript 1 end subscript and mass 2 m is placed at y subscript 2 end subscript.
    Taking point c at the origin position vector of points y subscript 1 end subscript a n d blank y subscript 2 end subscript can be written as
    r subscript 1 end subscript equals 2 l j comma blank r subscript 2 end subscript equals l j
    and m subscript 1 end subscript equals m a n d m subscript 2 end subscript equals 2 m
    Position vector of centre of mass of the system
    r subscript C M end subscript equals fraction numerator m subscript 1 end subscript r subscript 1 end subscript plus m subscript 2 end subscript r subscript 2 end subscript over denominator m plus m subscript 2 end subscript end fraction equals fraction numerator m 2 l stack j with hat on top plus 2 m l stack j with hat on top over denominator m plus 2 m end fraction equals fraction numerator 4 m l stack j with hat on top over denominator 3 m end fraction equals fraction numerator 4 l stack j with hat on top over denominator 3 end fraction
    General
    physics-

    Two balls each of mass m are placed on the vertices A and B of an equilateral triangle A B C of side 1m. A ball of mass 2m is placed at vertex C. The centre of mass of this system from vertex A (located at origin) is

    The centre of mass is given by

    stack x with minus on top equals fraction numerator m subscript 1 end subscript x subscript 1 end subscript plus m subscript 2 end subscript x subscript 2 end subscript plus m subscript 3 end subscript x subscript 3 end subscript over denominator m subscript 1 end subscript plus m subscript 2 end subscript plus m subscript 3 end subscript end fraction
    stack x with minus on top equals fraction numerator m cross times 0 plus m cross times 1 plus 2 m cross times open parentheses fraction numerator 1 over denominator 2 end fraction close parentheses over denominator m plus m plus 2 m end fraction
    stack x with minus on top equals fraction numerator 2 m over denominator 4 m end fraction equals fraction numerator 1 over denominator 2 end fraction m
    stack y with minus on top equals fraction numerator m subscript 1 end subscript y subscript 1 end subscript plus m subscript 2 end subscript y subscript 2 end subscript plus m subscript 3 end subscript y subscript 3 end subscript over denominator m subscript 1 end subscript plus m subscript 2 end subscript plus m subscript 3 end subscript end fraction
    stack y with minus on top equals fraction numerator m cross times 0 plus m cross times 0 plus 2 m cross times square root of 3 divided by 2 over denominator m plus m plus 2 m end fraction
    equals fraction numerator square root of 3 over denominator 4 end fractionm
    therefore Centre of mass is open parentheses fraction numerator 1 over denominator 2 end fraction m comma fraction numerator square root of 3 over denominator 4 end fraction m close parentheses.

    Two balls each of mass m are placed on the vertices A and B of an equilateral triangle A B C of side 1m. A ball of mass 2m is placed at vertex C. The centre of mass of this system from vertex A (located at origin) is

    physics-General
    The centre of mass is given by

    stack x with minus on top equals fraction numerator m subscript 1 end subscript x subscript 1 end subscript plus m subscript 2 end subscript x subscript 2 end subscript plus m subscript 3 end subscript x subscript 3 end subscript over denominator m subscript 1 end subscript plus m subscript 2 end subscript plus m subscript 3 end subscript end fraction
    stack x with minus on top equals fraction numerator m cross times 0 plus m cross times 1 plus 2 m cross times open parentheses fraction numerator 1 over denominator 2 end fraction close parentheses over denominator m plus m plus 2 m end fraction
    stack x with minus on top equals fraction numerator 2 m over denominator 4 m end fraction equals fraction numerator 1 over denominator 2 end fraction m
    stack y with minus on top equals fraction numerator m subscript 1 end subscript y subscript 1 end subscript plus m subscript 2 end subscript y subscript 2 end subscript plus m subscript 3 end subscript y subscript 3 end subscript over denominator m subscript 1 end subscript plus m subscript 2 end subscript plus m subscript 3 end subscript end fraction
    stack y with minus on top equals fraction numerator m cross times 0 plus m cross times 0 plus 2 m cross times square root of 3 divided by 2 over denominator m plus m plus 2 m end fraction
    equals fraction numerator square root of 3 over denominator 4 end fractionm
    therefore Centre of mass is open parentheses fraction numerator 1 over denominator 2 end fraction m comma fraction numerator square root of 3 over denominator 4 end fraction m close parentheses.
    General
    physics-

    Three identical spheres, each of mass 1 kg are kept as shown in figure below, touching each other, with their centers on a straight line. If their centres are marked P,Q, R blankrespectively, the distance of centre of mass of the system from P is

    ) fraction numerator P Q plus Q R plus P R over denominator 6 end fraction
    Distance of centre of mass from P is
    r equals fraction numerator r subscript 1 end subscript plus r subscript 2 end subscript plus r subscript 3 end subscript over denominator 3 end fraction equals fraction numerator 0 plus P Q plus P R over denominator 3 end fraction equals fraction numerator P Q plus P R over denominator 3 end fraction

    Three identical spheres, each of mass 1 kg are kept as shown in figure below, touching each other, with their centers on a straight line. If their centres are marked P,Q, R blankrespectively, the distance of centre of mass of the system from P is

    physics-General
    ) fraction numerator P Q plus Q R plus P R over denominator 6 end fraction
    Distance of centre of mass from P is
    r equals fraction numerator r subscript 1 end subscript plus r subscript 2 end subscript plus r subscript 3 end subscript over denominator 3 end fraction equals fraction numerator 0 plus P Q plus P R over denominator 3 end fraction equals fraction numerator P Q plus P R over denominator 3 end fraction
    General
    physics-

    From a circular disc of radius R and mass 9 M, a small disc of radius R/3 is removed from the disc. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through O is

    I subscript r e m a i n i n g end subscript equals I subscript w h o l e end subscript minus I subscript r e m o v e d end subscript
    or I equals fraction numerator 1 over denominator 2 end fraction open parentheses 9 M close parentheses open parentheses R to the power of 2 end exponent close parentheses minus open square brackets fraction numerator 1 over denominator 2 end fraction m open parentheses fraction numerator R over denominator 3 end fraction close parentheses to the power of 2 end exponent plus fraction numerator 1 over denominator 2 end fraction m open parentheses fraction numerator 2 R over denominator 3 end fraction close parentheses to the power of 2 end exponent close square brackets (i)
    Here, m equals fraction numerator 9 M over denominator pi R to the power of 2 end exponent end fraction cross times pi open parentheses fraction numerator R over denominator 3 end fraction close parentheses to the power of 2 end exponent equals M
    Substituting in Eq. (i), we have
    I equals 4 M R to the power of 2 end exponent

    From a circular disc of radius R and mass 9 M, a small disc of radius R/3 is removed from the disc. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through O is

    physics-General
    I subscript r e m a i n i n g end subscript equals I subscript w h o l e end subscript minus I subscript r e m o v e d end subscript
    or I equals fraction numerator 1 over denominator 2 end fraction open parentheses 9 M close parentheses open parentheses R to the power of 2 end exponent close parentheses minus open square brackets fraction numerator 1 over denominator 2 end fraction m open parentheses fraction numerator R over denominator 3 end fraction close parentheses to the power of 2 end exponent plus fraction numerator 1 over denominator 2 end fraction m open parentheses fraction numerator 2 R over denominator 3 end fraction close parentheses to the power of 2 end exponent close square brackets (i)
    Here, m equals fraction numerator 9 M over denominator pi R to the power of 2 end exponent end fraction cross times pi open parentheses fraction numerator R over denominator 3 end fraction close parentheses to the power of 2 end exponent equals M
    Substituting in Eq. (i), we have
    I equals 4 M R to the power of 2 end exponent
    General
    chemistry-

    WhatweightofHNO3isneededtoconvert 62gmofP4 inH3PO4 ithreaction? P4 +HNO3 →H3PO4 +NO2 +H2O

    WhatweightofHNO3isneededtoconvert 62gmofP4 inH3PO4 ithreaction? P4 +HNO3 →H3PO4 +NO2 +H2O

    chemistry-General