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Question

Lt subscript x not stretchy rightwards arrow 1 end subscript invisible function application fraction numerator cube root of x minus 1 over denominator x minus 1 end fraction

  1. 2 over 3    
  2. 3 over 2    
  3. 1 third    
  4. 1 half    

The correct answer is: 2 over 3


    limit as x rightwards arrow 1 of fraction numerator cube root of x minus 1 over denominator x minus 1 end fraction
equals limit as x rightwards arrow 1 of fraction numerator cube root of x minus cube root of 1 over denominator open parentheses cube root of x close parentheses cubed minus open parentheses cube root of 1 close parentheses cubed end fraction
equals limit as x rightwards arrow 1 of fraction numerator cube root of x minus cube root of 1 over denominator open parentheses cube root of x minus cube root of 1 close parentheses open parentheses open parentheses x close parentheses to the power of begin display style 2 over 3 end style end exponent plus open parentheses x close parentheses to the power of begin display style 1 third end style end exponent plus 1 close parentheses end fraction
equals limit as x rightwards arrow 1 of open parentheses fraction numerator 1 over denominator open parentheses open parentheses x close parentheses to the power of 2 over 3 end exponent plus open parentheses x close parentheses to the power of 1 third end exponent plus 1 close parentheses end fraction close parentheses
equals fraction numerator 1 over denominator 1 plus 1 plus 1 end fraction
equals 1 third

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