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Lt subscript x not stretchy rightwards arrow 0 end subscript fraction numerator cos a x minus cos b x over denominator x squared end fraction

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  1. fraction numerator a squared minus b squared over denominator 2 end fraction
  2. fraction numerator b squared minus a squared over denominator 2 end fraction    
  3. fraction numerator a squared plus b squared over denominator 2 end fraction    
  4. 2 open parentheses a squared minus b squared close parentheses    

    Answer:The correct answer is: fraction numerator b squared minus a squared over denominator 2 end fraction

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