Biology

General

Easy

Question

# Organisms which obtain energy by the oxidation of reduced inorganic compounds are called:

- saprozoic
- chemoautotrophs
- photoautotrophs
- coproheterotrophs

## The correct answer is: chemoautotrophs

### Related Questions to study

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### Finding of Miller's experiment on origin of life has provided evidence for:

### Finding of Miller's experiment on origin of life has provided evidence for:

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### The number of codons that code different amino acids is -

### The number of codons that code different amino acids is -

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### Assertion (A):If $a>0,b>0$ and $c>0$, then $(a+b+c)(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})\ge 9$Reason (R): For positive numbers $a,$ $b,$ $c,$ $AM\ge GM$

$AM\ge GM$$=\succ \frac{\frac{1}{a}+\frac{1}{b}+\frac{1}{c}}{3}\ge \left(\begin{array}{cc}111& \\ -& -\\ \overline{b}a.& c\end{array}\right)\to \left(1\right)$$D:{x}^{2}-3x-4<0\supset (x+1)(x-4)<0\Rightarrow 1<x<4$${x}^{2}-3x+2>0Rejectx-2\left)\right(x-1)>0=x<1{a}^{r}x>2$$\frac{(a+b+c)}{3}\ge (abc{)}^{\frac{1}{3}}\to (2)$multiply (1) and (2)

### Assertion (A):If $a>0,b>0$ and $c>0$, then $(a+b+c)(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})\ge 9$Reason (R): For positive numbers $a,$ $b,$ $c,$ $AM\ge GM$

maths-General

$AM\ge GM$$=\succ \frac{\frac{1}{a}+\frac{1}{b}+\frac{1}{c}}{3}\ge \left(\begin{array}{cc}111& \\ -& -\\ \overline{b}a.& c\end{array}\right)\to \left(1\right)$$D:{x}^{2}-3x-4<0\supset (x+1)(x-4)<0\Rightarrow 1<x<4$${x}^{2}-3x+2>0Rejectx-2\left)\right(x-1)>0=x<1{a}^{r}x>2$$\frac{(a+b+c)}{3}\ge (abc{)}^{\frac{1}{3}}\to (2)$multiply (1) and (2)

maths-

### The length of the chord joining the points $\left(4\mathrm{cos}\theta ,4\mathrm{sin}\theta \right)$ and $(4\mathrm{cos}\left(\theta +60\xb0\right),4\mathrm{sin}(\theta +60\xb0)$of the circle ${x}^{2}+{y}^{2}=16$ is

### The length of the chord joining the points $\left(4\mathrm{cos}\theta ,4\mathrm{sin}\theta \right)$ and $(4\mathrm{cos}\left(\theta +60\xb0\right),4\mathrm{sin}(\theta +60\xb0)$of the circle ${x}^{2}+{y}^{2}=16$ is

maths-General

Physics-

In an orbital motion, the angular momentum vector is

In an orbital motion, the angular momentum vector is

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### If the two curves and touch each other at (0,1) then the equation of the common tangent is

### If the two curves and touch each other at (0,1) then the equation of the common tangent is

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### At (1,1), the two curves and

### At (1,1), the two curves and

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### The slope of the curve at is 1, then k is

### The slope of the curve at is 1, then k is

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### _________ is isostructrual with diamond

### _________ is isostructrual with diamond

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maths-

### Observe the following statements and choose correct answer Statement-I:A particle p moves along a straight line, starting from a fixed point ‘O’, obeying s=16+48t-${t}^{3}.$the direction of p when t=5 is along $\overline{OP}$ Statement-II: For a particle moving on a line, if velocity v<0 then the body moves towards the initial point.

Statement -I:

### Observe the following statements and choose correct answer Statement-I:A particle p moves along a straight line, starting from a fixed point ‘O’, obeying s=16+48t-${t}^{3}.$the direction of p when t=5 is along $\overline{OP}$ Statement-II: For a particle moving on a line, if velocity v<0 then the body moves towards the initial point.

maths-General

Statement -I:

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### Statement ‐ I : The equation $z\overline{z}+\overline{a}z+a\overline{z}+\lambda =0$ where a is a complex number, represents a circle in Argand plane if $\lambda $ is real. Statement ‐II : The radius of the circle $z\overline{z}+\overline{a}z+a\overline{z}+\lambda =0$ is $\sqrt{\lambda -a\overline{a}}$

Result

### Statement ‐ I : The equation $z\overline{z}+\overline{a}z+a\overline{z}+\lambda =0$ where a is a complex number, represents a circle in Argand plane if $\lambda $ is real. Statement ‐II : The radius of the circle $z\overline{z}+\overline{a}z+a\overline{z}+\lambda =0$ is $\sqrt{\lambda -a\overline{a}}$

maths-General

Result

GeneralVideo

### Divide the following fractions:

Here, we have to divide the given fractions.

Now, 2/11 ÷ 9/22

= 2/11 × 22/9

= 2/1 × 2/9

= 2 × 2 / 1 × 9

= 4/9

Hence, the correct option is (a).

Now, 2/11 ÷ 9/22

= 2/11 × 22/9

= 2/1 × 2/9

= 2 × 2 / 1 × 9

= 4/9

Hence, the correct option is (a).

### Divide the following fractions:

GeneralGeneral

Here, we have to divide the given fractions.

Now, 2/11 ÷ 9/22

= 2/11 × 22/9

= 2/1 × 2/9

= 2 × 2 / 1 × 9

= 4/9

Hence, the correct option is (a).

Now, 2/11 ÷ 9/22

= 2/11 × 22/9

= 2/1 × 2/9

= 2 × 2 / 1 × 9

= 4/9

Hence, the correct option is (a).

biology

### The third cleavage in frog's development is

### The third cleavage in frog's development is

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### The reason why the right kidney is slightly lower than the left is:

Excretion involves the processes in which substances of no further use or those present in excess qualities are thrown out of the body.

### The reason why the right kidney is slightly lower than the left is:

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Excretion involves the processes in which substances of no further use or those present in excess qualities are thrown out of the body.

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### Consider the following boron halides

I)

II)

III)

IV)

The Lewis acid characters of these halides are such that

### Consider the following boron halides

I)

II)

III)

IV)

The Lewis acid characters of these halides are such that

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