Biology
General
Easy

Question

The given figure shows an angiogram of the coronary blood vessel. Which one of the following statements correctly describes, what is being done?

  1. It is a coronary artery which has a cancerous growth that is being removed.    
  2. It is a coronary artery which is blocked by a plaque and the same is being cracked.    
  3. It is a coronary vein in which the defective valves are being opened.    
  4. It is a coronary vein blocked by a parasite (blood fluke) that is being removed.    

The correct answer is: It is a coronary artery which is blocked by a plaque and the same is being cracked.

Related Questions to study

General
Maths-

There are 3 letters and 3 addressed envelopes corresponding to them. The number of ways in which the letters be placed in the envelopes so that no letter is in the right envelope is:

Total number ways in which 3 letters can be put in 3 different envelopes= 3! = 6
now, numbers of ways when only 1 letter is put in the right envelope = blank cubed C subscript 1=3
number of ways when 2 letters are put in the right envelope = 0
as when we put 2 letters in the right envelope the third letter would be automatically in the right envelope
number of ways when 3 letters are put in the right envelope = 1
So, the no. of ways when no letter will be in the right envelope=6-(3+0+1) =6-4 =2

There are 3 letters and 3 addressed envelopes corresponding to them. The number of ways in which the letters be placed in the envelopes so that no letter is in the right envelope is:

Maths-General
Total number ways in which 3 letters can be put in 3 different envelopes= 3! = 6
now, numbers of ways when only 1 letter is put in the right envelope = blank cubed C subscript 1=3
number of ways when 2 letters are put in the right envelope = 0
as when we put 2 letters in the right envelope the third letter would be automatically in the right envelope
number of ways when 3 letters are put in the right envelope = 1
So, the no. of ways when no letter will be in the right envelope=6-(3+0+1) =6-4 =2
General
biology

Match Column - I with Column - II and select the correct option from the codes give below.

Match Column - I with Column - II and select the correct option from the codes give below.

biologyGeneral
General
Maths-

The sum of all the numbers formed by taking all the digits from 3,4,5,6,7 is:

The number of numbers having 3 in the unit place= 4! =24
The number of numbers having 4 in the unit place= 4! =24
The number of numbers having 5 in the unit place= 4! =24
The number of numbers having 6 in the unit place= 4! =24
The number of numbers having 7 in the unit place= 4! =24
So the sum of the digits in the unit place of all the numbers=3 cross times 24 plus 4 cross times 24 plus 5 cross times 24 plus 6 cross times 24 plus 7 cross times 24
=24(3+4+5+6+7)
=24cross times25=600
Similarly the sum of the digits of all the numbers in each of the other places=600
The required sum =600 cross times 10000 plus 600 cross times 1000 plus 600 cross times 100 plus 600 cross times 10 plus 600 cross times 1
=600(10000+1000+100+10+1)
=600(11111)
=6666600

The sum of all the numbers formed by taking all the digits from 3,4,5,6,7 is:

Maths-General
The number of numbers having 3 in the unit place= 4! =24
The number of numbers having 4 in the unit place= 4! =24
The number of numbers having 5 in the unit place= 4! =24
The number of numbers having 6 in the unit place= 4! =24
The number of numbers having 7 in the unit place= 4! =24
So the sum of the digits in the unit place of all the numbers=3 cross times 24 plus 4 cross times 24 plus 5 cross times 24 plus 6 cross times 24 plus 7 cross times 24
=24(3+4+5+6+7)
=24cross times25=600
Similarly the sum of the digits of all the numbers in each of the other places=600
The required sum =600 cross times 10000 plus 600 cross times 1000 plus 600 cross times 100 plus 600 cross times 10 plus 600 cross times 1
=600(10000+1000+100+10+1)
=600(11111)
=6666600
parallel
General
Maths-

The sum of all the numbers formed by taking all the digits from 2,3,4,5 is:

The number of numbers having 2 in the unit place= 3! =6
The number of numbers having 3 in the unit place= 3! =6
The number of numbers having 4 in the unit place= 3! =6
The number of numbers having 5 in the unit place= 3! =6
So the sum of the digits in the unit place of all the numbers=2 cross times 6 plus 3 cross times 6 plus 4 cross times 6 plus 5 cross times 6
=12+18+24+30
=84
Similarly the sum of the digits of all the numbers in each of the other places=84
The required sum =84 cross times 1000 plus 84 cross times 100 plus 84 cross times 10 plus 84
=84(1000+100+10+1)
=84cross times 1111
=93324

The sum of all the numbers formed by taking all the digits from 2,3,4,5 is:

Maths-General
The number of numbers having 2 in the unit place= 3! =6
The number of numbers having 3 in the unit place= 3! =6
The number of numbers having 4 in the unit place= 3! =6
The number of numbers having 5 in the unit place= 3! =6
So the sum of the digits in the unit place of all the numbers=2 cross times 6 plus 3 cross times 6 plus 4 cross times 6 plus 5 cross times 6
=12+18+24+30
=84
Similarly the sum of the digits of all the numbers in each of the other places=84
The required sum =84 cross times 1000 plus 84 cross times 100 plus 84 cross times 10 plus 84
=84(1000+100+10+1)
=84cross times 1111
=93324
General
Maths-

The number of constant mappings from A equals left curly bracket 1 comma 2 comma 3 comma 4 horizontal ellipsis horizontal ellipsis comma n right curly bracket to B equals left curly bracket a comma b right curly bracket is

The number of constant mappings from A equals left curly bracket 1 comma 2 comma 3 comma 4 horizontal ellipsis horizontal ellipsis comma n right curly bracket to B equals left curly bracket a comma b right curly bracket is 2.

The number of constant mappings from A equals left curly bracket 1 comma 2 comma 3 comma 4 horizontal ellipsis horizontal ellipsis comma n right curly bracket to B equals left curly bracket a comma b right curly bracket is

Maths-General
The number of constant mappings from A equals left curly bracket 1 comma 2 comma 3 comma 4 horizontal ellipsis horizontal ellipsis comma n right curly bracket to B equals left curly bracket a comma b right curly bracket is 2.
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The number of many one functions from A equals left curly bracket 1 comma 2 comma 3 right curly bracket text  to  end text B equals left curly bracket a comma b comma c comma d right curly bracket is

Given, A{1, 2, 3} and B{a, b, c, d}

Element A can have an image in 3 ways, i.e., (1, 2, 3)

Similarly, B can have an image in 4 ways.

Thus, total number of ways =4×4×4=64

The number of many one functions from A equals left curly bracket 1 comma 2 comma 3 right curly bracket text  to  end text B equals left curly bracket a comma b comma c comma d right curly bracket is

Maths-General
Given, A{1, 2, 3} and B{a, b, c, d}

Element A can have an image in 3 ways, i.e., (1, 2, 3)

Similarly, B can have an image in 4 ways.

Thus, total number of ways =4×4×4=64

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The number of into functions that can be defined from A equals left curly bracket x comma y comma z comma w comma t right curly bracket text  to  end text bold italic B equals left curly bracket bold italic alpha comma bold italic beta comma bold italic gamma right curly bracket is

 

The number of into functions that can be defined from A equals left curly bracket x comma y comma z comma w comma t right curly bracket text  to  end text bold italic B equals left curly bracket bold italic alpha comma bold italic beta comma bold italic gamma right curly bracket is

 

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A body moving with velocity v has momentum and kinetic energy numerically equal. What is the value of v?

A body moving with velocity v has momentum and kinetic energy numerically equal. What is the value of v?

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The graph between the resistive force F acting on a body and the distance covered by the body is shown in figure. The mass of the body is 25KG and initial velocity is 2 m/s. When the distance covered by the body is 4km, its kinetic energy would be

The graph between the resistive force F acting on a body and the distance covered by the body is shown in figure. The mass of the body is 25KG and initial velocity is 2 m/s. When the distance covered by the body is 4km, its kinetic energy would be

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The number of onto functions that can be defined from A={a,b,c,d,e} to {1,2} is

Given, A{abcd, e} and B{,2}

Element a can has an image in 2 ways, i.e., (1 or 2).

Similarly, a, bc, d and e can have an image in 5 ways.

Thus, total number of ways =2×2×2×2×2=32

The number of onto functions that can be defined from A={a,b,c,d,e} to {1,2} is

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Given, A{abcd, e} and B{,2}

Element a can has an image in 2 ways, i.e., (1 or 2).

Similarly, a, bc, d and e can have an image in 5 ways.

Thus, total number of ways =2×2×2×2×2=32

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The momentum of a body increases by 20%. The percentage increase in its kinetic energy is

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A block of mass 10 kg slides down a rough slope which is inclined at 45 to the power of ring operator to the horizontal. The coefficient of sliding friction is 0.30. When the block has slide 5 m, the work done on the block by the force of friction is nearly

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Two identical cylindrical vessels with their bases at same level each contains a liquid of density rho. The height of the liquid in vessel is h1 and that in the other vessel is h2. The area of either base is A. The work done by gravity in equalizing the levels when the two vessels are connected, is

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The number of injections from Set - A containing 5 elements to a Set -B containing 6 elements is

The number of injections from Set - A containing 5 elements to a Set -B containing 6 elements isblank to the power of 6 P subscript 5

The number of injections from Set - A containing 5 elements to a Set -B containing 6 elements is

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The number of injections from Set - A containing 5 elements to a Set -B containing 6 elements isblank to the power of 6 P subscript 5
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