Botany-
General
Easy

Question

Tangent at any point of ellipse 9 x to the power of 2 end exponent plus 16 y to the power of 2 end exponent minus 144 equals 0 is drawn. Eccentric
angle of ‘ P’ is theta equals fraction numerator 1 over denominator 2 end fraction s i n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator 7 end fraction close parentheses If is the foot of perpendicular from centre blank ´ O blank ´ to this tangent then angle P O N is

  1.  t a n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator 12 end fraction close parentheses  
  2.   t a n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator 24 end fraction close parentheses   
  3.  fraction numerator pi over denominator 12 end fraction  
  4. fraction numerator pi over denominator 3 end fraction  

The correct answer is:
t a n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator 24 end fraction close parentheses



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