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# Calculateenthalpychangeofthefollowingreaction H2C=CH2(g)+H2(g)→H3C–CH3(g) ThebondenergiesofC–H,C–C,C=C,H–Hare414, 347,615and435KJmol–1respectively-

- 125KJmol–1
- –125KJmol–1
- 250KJmol–1
- –25KJmol–1

## The correct answer is: –125KJmol–1

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