Chemistry-

General

Easy

Question

# Consider the following processes: DH(kJ/mol) ½A→B +150 3B→2C+D–125 E+A→2D+350 ForB+D→E+2C,DHillbe-

- 325kJ/mol
- 525kJ/mol
- –175kJ.mol
- –325kJ/mol

## The correct answer is: –175kJ.mol

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